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balu736 [363]
3 years ago
15

Jennifer starts with a population of 100 amoebas that doubles in size every minute for a number of minutes, m. She writes the ex

pression 100(2m) to find the number of amoeba after m minutes. Nathan starts with a population of 10 amoebas that increases 40% in size every minute for a number of minutes, m. He writes the expression (1+0.4)m to find the number of amoeba after m minutes. Use the drop-down menus to explain what each part of Jennifer's and Nathan's expressions mean.
Mathematics
1 answer:
Zina [86]3 years ago
7 0

Answer:

100(2m)

(1+0.4)

Nathan=0.4 is the percent added =the 40 percent added to the 10 amoebas

Jennifer=the first equation is how many total amoebas Jennifer has in total

<h3><u>Hope this helps!</u></h3>
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Initially a wheel rotating about a fixed axis at a constant angular deceleration of 0.5 rad/s 2 has an angular velocity of 0 rad
Zigmanuir [339]

Answer:

\theta = 5.83\ rad

Step-by-step explanation:

given,

angular deceleration, α = -0.5 rad/s²

final angular velocity,ω_f = 0 rad/s

angular position, θ = 6.1 rad

angular position at 3.9 s = ?

now, Calculating the initial angular speed

\omega_f^2 = \omega_i^2 + 2 \alpha \theta

0 = \omega_i^2 - 2\times 0.5\times 6.1

\omega_i = \sqrt{6.1}

\omega_i = 2.47\ rad/s

now, angular position calculation at t=3.9 s

\theta = \omega_i t + \dfrac{1}{2}\alpha t^2

\theta =2.47\times 3.9 - \dfrac{1}{2}\times 0.5\times 3.9^2

\theta = 5.83\ rad

Hence, the angular position of the wheel after 3.9 s is equal to 5.83 rad.

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3 years ago
HELP PLEASE SUPER QUICK, I'LL MARK AS BRAINLIEST!
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Answer:

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3 years ago
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Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 50 meters. What is the diagonal d
jolli1 [7]

Answer:

70.7 meters.

Step-by-step explanation:

We have been given that Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 50 meters.

Since we know that diagonal of a square is product of side length of square and \sqrt{2}. So we will find diagonal of our given square plaza by multiplying 50 by \sqrt{2}.

\text{Diagonal distance across the plaza}=50\times \sqrt{2}

\text{Diagonal distance across the plaza}=50\times 1.414213562373095

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3 years ago
The sum of two numbers is 56. One number is 3 times as large as the other. What are the numbers?
MissTica
42 and 14

explanation:

x+y = 56
x = 3y

Substitute for x in the first equation:
x + y = 56
x = 3y
3y + y = 56
Combine like terms:
4y = 56
Divide both sides by 4:
y = 14

So if y = 14, and x = 3y, then x = 42.

Now substitute for both x and y in both of the original equations to prove they are the correct values.

x + y = 56
x = 42
y = 4
42 + 14 = 56
56 = 56

x = 3y
x = 42
y = 14
42 = 3*14
42 = 42

So the two numbers, x and y, are 42 and 14.
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