Question

Please help me solve this answer it all for me please

Answer 1

Answer:

The slopes are

$m1=\dfrac{2}{5}, m2=-\dfrac{5}{2}$

Therefore, the equations are equations of  Perpendicular Lines .

Step-by-step explanation:

Given:

$y=\dfrac{2}{5}\times x + 1$    ......................Equation ( 1 )

$5x+2y=-4\\\\\therefore y = \dfrac{-5}{2}\times x-2$   ..............Equation ( 2 )

To Find:

Slope of equation 1 = ?

Slope of equation 2 = ?

Solution:

On comparing with slope point form

$y=mx+c$

Where,

m = Slope

c = y-intercept

We get

Step 1.

Slope of equation 1 = m1 = $\dfrac{2}{5}$

Step 2.

Slope of equation 1 = m2 = $-\dfrac{5}{2}$

Step 3.

Product of Slopes = m1 × m2 = $\dfrac{2}{5}\times -\dfrac{5}{2}=-1$

Product of Slopes = m1 × m2 = -1

Which is the condition for Perpendicular Lines

The slopes are

$m1=\dfrac{2}{5},m2=-\dfrac{5}{2}$

Therefore, the equations are equations of  Perpendicular Lines .