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Novosadov [1.4K]
4 years ago
6

Draw the three structures of the aldehydes with molecular formula C5H10O that contain a branched chain.

Chemistry
1 answer:
crimeas [40]4 years ago
7 0

Answer:

See picture for answer

Explanation:

First to all, an aldehyde is a carbonated chain with a Carbonile within it chain. It's call aldehyde basically because the C = O is always at the end of the chain. When the C = O is on another position of the chain, is called a ketone.

Now, in this exercise we have an aldehyde with 5 carbons, so the first carbon is the C = O. The remaining four carbon belong to the chain. however, we need to have a branched chain in this molecular formula.

If this the case, this means that the longest chain cannot have 5 carbons. It should have 4 carbons as the longest chain. The remaining carbon, would one branched.

In this case, we only have two possible ways to have an aldehyde with a branched chain, and 4 carbons at max. One methyl in position 2, and the other in position 3.

The remaining aldehyde with branched chain, cannot have 4 carbons as longest, it should have 3 carbons with longest chain and 2 carbons as radicals (In this case, methyl). In this way, we just have all the aldehyde with this formula and at least one branched chain. The other possible ways would be conformers or isomers of the first three.

See picture for the structures of these 3 aldehydes, and their names.}

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For the first ionization energy for an N2 molecule, what molecular orbital is the electron removed from
olga55 [171]

Answer:

p orbital.

Explanation:

Valence electrons are the electrons in an atom holding the very last orbital which is used in chemical bonding with other elements. Their existence could define the chemical properties of that atom.

During the first energy in ionization of an N2 molecule the molecular orbital from which the electron could be extracted is the only one with the highest energy level. Nitrogen has its outermost orbital (p) containing three valence electrons. Each orbital is only half filled, and thus it is unstable Thus, the electron mission must have been removed from p orbital.

7 0
3 years ago
A 2.600×10−2 M solution of glycerol (C3H8O3) in water is at 20.0∘C. The sample was created by dissolving a sample of C3H8O3 in w
sesenic [268]

Answer:

A. 0.2395 w/w %

B. 2394ppm

Explanation:

A. To find concentrationin percent by mass of the solution we need to calculate mass of glycerol and mass of water. The formula is:

Mass glycerol / Total mass * 100

<em>Mass glycerol:</em>

The solution is 2.6x10⁻²moles / L. As there is 1L of solution there are 2.6x10⁻² moles of glycerol. In mass (Using molar mass glycerol: 92.09g/mol):

2.6x10⁻² moles of glycerol * (92.09g / mol) = 2.394g glycerol

<em>Mass of water:</em>

998.9mL and density = 0.9982g/mL:

998.9mL * (0.9982g/mL) = 997.1g of water.

That means percent by mass is:

% by mass: 2.394g / (997.1g + 2.394g) * 100 = 0.2395 w/w %

B. Parts per million are mg of glycerol per L of solution. As in 1L there are 2.394g. In mg:

2.394g * (1000mg / 1g) = 2394mg:

Parts per million: 2394mg / L = 2394ppm

3 0
3 years ago
If two electrons have same number of protons but different number of neutrons can they be atoms of the same element?
Illusion [34]
If two atoms** have the same number of protons, they are the same element. They have the same atomic number. The only thing that would change with the number of neutrons is the mass number.
6 0
3 years ago
Help me out please due tomorrow
skelet666 [1.2K]
I'm pretty sure number 48 is C. Hope this helped :)
6 0
3 years ago
Read 2 more answers
A bicycle tire has a volume of 1.0 l at 22°c. if the temperature of the tire is increased to 52°c, what is the resulting volume
tresset_1 [31]

The relationship between the volume, temperature, and pressure of the gas can be given by Charles law. The volume of the tire is 1.1 L.

<h3>What is Charle's law?</h3>

According to Charles's law, the volume is directly proportional to the temperature of the gas at a constant pressure.

Charle's law can be shown as,

\rm \dfrac{V_{1}}{T_{1}} = \rm \dfrac{V_{2}}{T_{2}}

Given,

Initial volume = 1.0 L

Initial temperature = 295 K

Final volume = ?

Final temperature = 325 K

Substituting values in the above equation the final volume can be calculated as:

\begin{aligned}\rm V_{2} &= \rm \dfrac{V_{1}T_{2}}{T_{1}}\\\\&= \dfrac{ 1 \times 325}{295}\\\\&= 1.1\;\rm L\end{aligned}

Therefore, the final resulting volume of the tire is 1.1 L.

Learn more about Charle's law here:

brainly.com/question/26849359

5 0
3 years ago
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