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3 years ago

7

Сколько граммов соли образуется, если в раствор, содержащий 9,8 г серной кислоты, добавим другой раствор, имеющего 10 г гидрокси

да натрия?

1 answer:

lutik1710 [3]3 years ago

3 0

What language is even this Oop i DONT know good luck

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2 years ago

PLEASE ANSWER CORRECTLY PLEASE

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3 years ago

Calculate the volume in liters of a 0.00231M copper(II) fluoride solution that contains 175.g of copper(II) fluoride CuF2. Be su

Free_Kalibri [48]

Answer:

Volume = 746 L

Explanation:

Given that:- Mass of copper(II) fluoride = 175 g

Molar mass of copper(II) fluoride = 101.543 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{175\ g}{101.543\ g/mol}$

$Moles_{copper(II)\ fluoride}= 1.7234\ mol$

Also,

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

So,,

$Volume =\frac{Moles\ of\ solute}{Molarity}$

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So,

$Volume =\frac{1.7234}{0.00231}\ L$

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3 years ago