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s344n2d4d5 [400]
2 years ago
13

Which is the most appropriate operation to use to solve this problem?

Mathematics
2 answers:
blagie [28]2 years ago
5 0
You would want to use division since you want to separate the cans evenly onto the shelves.
Charra [1.4K]2 years ago
3 0
B.
division
 
Cause the words:
<span>He has 585 cans to stack evenly on 15 shelves. gives us a clue.

If u ask for the answer it would be 39</span>
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Question 1/10 points)
lina2011 [118]

the 2nd expression is the answer

5 0
3 years ago
I need the slope of each line.. need the answer
s344n2d4d5 [400]
2 over -1 im pretty sure that's it we just learned this like 2 weeks ago
6 0
3 years ago
Last one plz help me!
Mashutka [201]

Answer:

a) no real solutions

Step-by-step explanation:

the discriminant (b² - 4ac) is negative which indicates no real solutions

3 0
3 years ago
Find the savings plan balance after 18 months with an APR of 3% and monthly payments of $200.
ArbitrLikvidat [17]

The saving plan balance is $3,677.53.

Given that,

  • The no of months is 18.
  • The annual percentage rate is 3% so the monthly rate percentage is 0.25%.
  • And, the monthly payment is $200.

Based on the above information, the following formula should be used:

FVA = PMT×  [(1+r)^n - 1] ÷ r

= $200 × [(1+ 0.0025)^18 - 1] ÷ 0.0025

= $3,677.53

Therefore we can conclude that the saving plan balance is $3,677.53.

Learn more: brainly.com/question/14191332

4 0
2 years ago
HELP PLEASE WILL MARK BRAINLIEST!!
Arte-miy333 [17]

Answer:

Answer is option d)346.4 ft

Step-by-step explanation:

from \: the \: figure \\ AB = 300 \: ft \:  \:  \: angle \: C = 60  \:( theta)\: degress \\ in \: triangle \: ABC \: using \:  tan \: theta\\  \tan(60)  =  \frac{opposite \: side}{adjacent \: side}  \\  \tan(60)  =  \frac{300}{BC}  \\  \sqrt{3}  =  \frac{300}{BC}  \\ BC =  \frac{300}{ \sqrt{3} }  \\ BC = 100 \sqrt{3} ft \\ then \: in \: triangle \: ABD \: using \: tan \: theta \\ angle \: D = 30 \: degrees \: (theta) \\   \tan(30 )  =\frac{opposite \: side}{adjacent \: side} \\  \tan(30)   =  \frac{300}{BD}  \\  \frac{1}{ \sqrt{ 3} }  =  \frac{300}{BD}  \\ BD = 300 \sqrt{3}  \\ CD = BD - BC \\  = 300 \sqrt{3 }  - 100 \sqrt{3}  \\  = (300 - 100) \sqrt{3}  \\  = 200 \sqrt{3 }  \\  = 200 \times 1.732 \\  = 346.4 \: ft

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

7 0
3 years ago
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