Answer:
4+x>13
x>9
Step-by-step explanation:
This statement represents an inequality. To solve for the missing number first write out the inequality algebrically.
"Four more" implies that 4 is being added to the number. Another way to "a number" is to use the variable, x. So, the left side of the inequality is 4+x. Then, it says that this is "more than" 13. Thus, the greater than sign, >, should be used. This means that the final inequality is 4+x>13.
Next, you can solve the inequality by subtracting 4 from both sides. This gives x>9.
401 ÷ 6 = 66.83 so id probably round it up to 66
T = 1/2
-6 = -12t
-6/-12 = t
6/12 = t
1/2 = t
Answer:
Step-by-step explanation:
The coordinates of M are calculated using the midpoint formula:
where 
and 
We substitute into the formula to obtain:
We simplify to get:
The coordinates of the midpoint of CD are:
Answer:
![P(Cube \ge 5\ and\ Spin[A]) = \frac{1}{24}](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29%20%3D%20%5Cfrac%7B1%7D%7B24%7D)
Step-by-step explanation:
Given
See attachment for spinner
Required
![P(Cube \ge 5\ and\ Spin[A])](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29)
On a number cube, we have:
---- i.e. 2 outcomes
So, the probability is:
On the spinner, we have:
![Spin [A] = \{A\}](https://tex.z-dn.net/?f=Spin%20%5BA%5D%20%3D%20%5C%7BA%5C%7D)
---- i.e. 1 outcomes
So, the probability is:
![P(Spin[A]) = \frac{n(Spin[A])}{n(Spinner)}](https://tex.z-dn.net/?f=P%28Spin%5BA%5D%29%20%3D%20%5Cfrac%7Bn%28Spin%5BA%5D%29%7D%7Bn%28Spinner%29%7D)
![P(Spin[A]) = \frac{1}{8}](https://tex.z-dn.net/?f=P%28Spin%5BA%5D%29%20%3D%20%5Cfrac%7B1%7D%7B8%7D)
is calculated as thus:
![P(Cube \ge 5\ and\ Spin[A]) = P(Cube \ge 5) * P(Spin[A])](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29%20%3D%20P%28Cube%20%5Cge%205%29%20%2A%20P%28Spin%5BA%5D%29)
![P(Cube \ge 5\ and\ Spin[A]) = \frac{1}{3} * \frac{1}{8}](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%2A%20%5Cfrac%7B1%7D%7B8%7D)
