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REY [17]
2 years ago
13

5. The area of a rectangular garden is 75 feet. If the length of the base is 15 feet, what is the

Mathematics
1 answer:
Lady_Fox [76]2 years ago
3 0
The height is 5 I believe
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Ghella [55]
It depends on whether you have "Perpendicular" or "base"
If you have perpendicular then, you can use the formula:
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cos Ф = B/ H

Hope this helps!
4 0
3 years ago
Light shines through window what is the area of a trapezoid shaped region created by the light
bogdanovich [222]

Answer:

16 ft²

Step-by-step explanation:

The complete question is attached.

A trapezoid is a quadrilateral (has four sides) with one a parallel base. The base angles and the diagonals of an isosceles trapezoid are equal.

The area of a trapezoid = [(sum of the parallel bases) / 2] * height of the trapezoid.

Given that the parallel bases are 3 ft and 5 ft, while the height of the trapezoid is 4 ft. Hence:

The area of a trapezoid = [(3 + 5)/2] * 4

The area of a trapezoid = 16 ft²

5 0
3 years ago
What is the additive inverse of the complex number -8 + 3i?<br> -8-3i<br> -8+3i<br> 8-3i<br> 8+3i
Nady [450]
The answer is b because the answer is b and the people don’t know how to do it
8 0
3 years ago
Read 2 more answers
The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s
Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that \mu = 1262, \sigma = 118

a) Determine the 26th percentile for the number of chocolate chips in a bag. ​

This is X when Z has a p-value of 0.26, so X when Z = -0.643.

Z = \frac{X - \mu}{\sigma}

-0.643 = \frac{X - 1262}{118}

X - 1262 = -0.643*118

X = 1186

(b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags.

Between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile.

2.5th percentile:

X when Z has a p-value of 0.025, so X when Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{X - 1262}{118}

X - 1262 = -1.96*118

X = 1031

97.5th percentile:

X when Z has a p-value of 0.975, so X when Z = 1.96.

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 1262}{118}

X - 1262 = 1.96*118

X = 1493

Between 1031 and 1493.

​(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip​ cookies?

Difference between the 75th percentile and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 1262}{118}

X - 1262 = -0.675*118

X = 1182

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 1262}{118}

X - 1262 = 0.675*118

X = 1342

IQR:

1342 - 1182 = 160

7 0
3 years ago
A group of college students are going to a lake house for the weekend and plan on renting small cars and large cars to make the
dangina [55]

The system of equations that could be used to determine the number of small cars rented and the number of large cars rented is;

x + y = 10

x + y = 105x + 7y = 66

<h3>Simultaneous equation</h3>

  • Small car = 5 people
  • Large car = 7 people
  • Total cars = 10
  • Total number of people = 66

Let

Number of small cars rented = x

Number of large cars rented = y

x + y = 10

x + y = 105x + 7y = 66

Learn more about simultaneous equation:

brainly.com/question/16863577

#SPJ1

3 0
2 years ago
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