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tia_tia [17]
3 years ago
10

Helpppppppppppppppppppppppppppppppppppppppppppppppppppppp

Mathematics
1 answer:
shepuryov [24]3 years ago
7 0
Lines are described by equations of the form y = mx + b
The fast way of finding 'b' is to look for a place where x = 0 and plug in the x and y values into this equation. In the case of this line, when x = 0, y = 5:

5 = m(0) + b
5 = 0 + b
5 = b

To get the slope, 'm', we need to pick two points and divide the difference of their y values by the difference of their x values. Pick points where the line falls on the grid. The one we just used, (0,5), works well. So does (2,1).

Plug into the equation m = (y2-y1)/(x2-x1) to get m = (1-5)/(2-0) = -4/2 = -2

Our equation is y = -2x + 5
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AB and BC form a right angle at point B if A = (-3,-1) and B = (4,4) what is the equation if BC
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Answer:

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Step-by-step explanation:

Refer the attached figure .

We are given a line AB

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Formula for slope 'm' when two points are given :

m=\frac{y_2-y_1}{x_2-x_1}

Substituting thew values

m=\frac{4-(-1)}{4-(-3)}

m=\frac{5}{7}

Since we are given that AB is perpendicular to BC

So, By property - perpendicular slopes are negative reciprocals of each other.

\Rightarrow m_1\times m_2 =-1

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\Rightarrow m_2 = \frac{-7}{5}

So, Slope for line BC : m_2 = \frac{-7}{5}

Point B = (4,4)

Formula of equation of line : y-y_1=m(x-x_1)

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5(y-4)=-7(x-4)

5y-20=-7x+28

7x+5y-20-28=0

7x+5y-48=0

Hence the equation of line BC : 7x+5y-48=0

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