If the roots to such a polynomial are 2 and

, then we can write it as

courtesy of the fundamental theorem of algebra. Now expanding yields

which would be the correct answer, but clearly this option is not listed. Which is silly, because none of the offered solutions are *the* polynomial of lowest degree and leading coefficient 1.
So this makes me think you're expected to increase the multiplicity of one of the given roots, or you're expected to pull another root out of thin air. Judging by the choices, I think it's the latter, and that you're somehow supposed to know to use

as a root. In this case, that would make our polynomial

so that the answer is (probably) the third choice.
Whoever originally wrote this question should reevaluate their word choice...
Step-by-step explanation:
SA=ph+2A, that is, perimeter × height+ twice area
p=21+20+29=70cm
h=22cm
70×22=1540cm
A=1/2 ×20×21=210×2=420
1540+420=1960cm2
c/2-3+6/d
substitute c=14 and d=13:
14/2-3+6/13
simplify:
7-3+6/13
4+6/13
multiply 4 by 13/13 to group like terms (for a fraction):
52/13+6/13
combine:
58/13
Therefore, the answer is 58/13 or around 4.462
Answer: Dim Col A = 4.
Step-by-step explanation:
Since we have given that
Matrix A has 5 rows and 8 columns.
And Nul A = 4
It implies that the rank of A would be
Number of columns - Nul A = 8 - 4 =4
So, rank A = 4
so, it has dim Col A = 4 also.
But the four vector basis lie in R⁵.
Hence, Dim Col A = 4.