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IgorLugansk [536]
4 years ago
11

What are the products of the double-replacement reaction between potassium bromide and silver nitrate? Name the resulting compou

nds.
Chemistry
2 answers:
stepladder [879]4 years ago
7 0
Nitrogen and oxygen is the answer
puteri [66]4 years ago
5 0
 silver nitrate is AgNO3 potassium bromide is KBr 
Each ion has single charge whether +ve or -ve. 
AgNO3(aq) + KBr(aq) = AgBr(s) + KNO3(aq) 
AgBr is water insoluble so precipitates. Potassium nitrate is soluble so stays in solution so can also be written as K+(aq) + NO3-(aq)
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1- Alum used in cooking is potassium aluminum sulfate hydrate, KAl(SO4)2. XH2O. To find the value of X, you can heat the sample
Burka [1]

Answer:

THE VALUE OF X IS 7 AND THE FORMULA OF THE HYDRATED SALT IS KAl(SO4)2.7H20

Explanation:

1. write out the varibales given in thequestion:

Mass of the hydrated salt = 4.74 g

Mass of water lost = 2.16 g

Formula of the hydrated salt = KAl(SO4)2. XH20

2. calculate the molar mass of the salt and that of water of crystallization:

Molar mass of anhydrous salt = ( K = 39, Al = 27, S = 32, 0=16)

= ( 39 + 27 + 32*2 + 16 * 8

= (39 + 27 + 64 + 128)

= 258 g/mol

Molar mass of water = 18 g/mol

3. Use this expression to calculate X:

The expression,

XH20 / molar mass of anhydrous salt = Mass of water lost / Mass of hydrated salt.

X = molar mass of anhydrous salt * mass of water lost / mass of anhydrous salt * H20

where XH20 is the molar mass of water of crystallization, is used to calculate the value of X.

4. Solve for X:

So therefore:

X = 258 * 2.16 / 4.74 * 18

X = 557.28/ 85.32

X = 6.53

X is approximately 7.

The value of X is 7 and the formula pf the hydrated salt is KAl(SO4)2.7H20

7 0
3 years ago
Define: 1. acids, 2. strong acids, 3. weak acids.
Reika [66]
H^+ = acid
OH^- = alkaline

Acids have a pH of below 7. The lower the number, the strongest the acid.
4 0
4 years ago
Read 2 more answers
How many grams of water will be produced from 50 g hydrogen reacting with 50 g oxygen?
DanielleElmas [232]

We need to first come up with a balanced equation:


4H+O_{2} → 2H_{2}O


We know that the molar ratio of hydrogen to oxygen to water now is 4:1:2.


Converting the amount of grams given to moles is as follows:


Hydrogen: \frac{1mole}{1.008g}*50g=49.6mol


Oxygen: \frac{1mole}{15.999g}*50g=3.125mol


We know now that the limiting reactant is oxygen. We can then know that the number of moles of water are produced are double the number of moles of oxygen used due to the ratio that we established at the beginning - 4:1:2.


So we now can use 6.25 moles of water as the amount produced.


Then we convert moles of water to grams:


\frac{18.015g}{1mole} *6.25mol=112.59g


Now we know that there are 112.59g of water produced when we start with 50g of hydrogen and 50g of water.

4 0
3 years ago
which statement besy describes how the calormeter can be used to determine ghe specific heat capacity of the metal sample
Vesna [10]

Answer:

Energy transfers to the metal from the water and calorimeter until they are all at room temperature.

Explanation:

i hope this helps

4 0
4 years ago
2 Na + 1 Cl2 → 2 Naci<br> How many grams of NaCl are created from 23,2 grams Cl2?
evablogger [386]

37 grams of NaCl (when I mean equivalent I mean the ratio of the equation is 1:2 for moles or Cl2 and NaCl

3 0
2 years ago
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