Find the value of x. (I've asked this question already and haven't gotten help.)

Mathematics

1 answer:

mixer [17]2 years ago

3 0

I put all of the answers through my calculator and it was the 8.33... that worked for me.

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Help i dont understand pls help :(

Scrat [10]

Answer:

Answer is h(0)=1

Step-by-step explanation:

All you have to do is substitute x with 0 in the original equation.

3 0

2 years ago

Which number number is equal to |-12|-|-3| ?

Vera_Pavlovna [14]

9 because the symbols around -12 and -3 so they would just become positive number 12 and 3. Subtract them and you get 9 :)

6 0

2 years ago

A total of 145 tickets were sold to a film showing bringing in a total of $1,153. Two types of tickets were sold: adult tickets

zalisa [80]

Supposing all were child tickets:
145x$5=$725
$1153-$725=$428 (diff. between above price and original price)
$9-$5=$4 (diff. between adult price and child price)
$428÷$4=107 (no. of adult tickets)

Ans: 107

3 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Montano1993 [528]

$x^2(4x-3)(5x-1)=0\iff x^2=0\ \vee\ 4x-3=0\ \vee\ 5x-1=0\\\\x^2=0\to\boxed{x=0}\\\\4x-3=0\ \ \ |+3\\4x=3\ \ \ |:4\\\boxed{x=\dfrac{3}{4}}\\\\5x-1=0\ \ \ |+1\\5x=1\ \ \ |:5\\\boxed{x=\dfrac{1}{5}}\\\\Answer:\ x=0\ or\ x=\dfrac{3}{4}\ or\ x=\dfrac{1}{5}$

6 0

2 years ago

Read 2 more answers

One side of a triangle is increasing at a rate of 9 cm/s and a second side is decreasing at a rate of 2 cm/s. if the area of the

LenKa [72]

Use the attached figure to guide yourself through the explanation. In the figure:
$a=21cm, b=36cm, \widehat{C}=\frac{\pi}{6}$ .
We know that:
$\frac{da}{dt}=9,\frac{db}{dt}=-2$
Also remmeber that the area of a triangle is:
$A=\frac{Base\times Height}{2}$
The hegiht is shown in the figure in red, the base is just the b side.
Using the angle C the area of the triangle is:
$A=\frac{1}{2}ab\cos(\widehat{C})\implies2A=ab\cos(\widehat{C})$
Now taking the derivative of the area 2A with respect to t we have:
$2\frac{dA}{dt}=b\cos(\widehat{C})\frac{da}{dt}+a\cos(\widehat{C})\frac{db}{dt}-ab\sin(\widehat{C})\frac{d\widehat{C}}{dt}$

Replacing with the right values:
$\frac{dA}{dt}=0\\
\\
\cos({\widehat{C}})=\frac{\sqrt{3}}{2}\\ \\
\sin({\widehat{C}})=\frac{1}{2}\\ \\

$
yields:
$0=36\frac{\sqrt{3}}{2}.9-21\frac{\sqrt{3}}{2}.2-\frac{1}{2}.21.36.\frac{d\widehat{C}}{dt}\implies \frac{d\widehat{C}}{dt}=\frac{141}{378}\sqrt{3}$

5 0

3 years ago