For the given function f(t) = (2t + 1) using definition of Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].
As given in the question,
Given function is equal to :
f(t) = 2t + 1
Simplify the given function using definition of Laplace transform we have,
L(f(t))s = 
= ![\int\limits^\infty_0[2t +1] e^{-st} dt](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%5Cinfty_0%5B2t%20%2B1%5D%20e%5E%7B-st%7D%20dt)
= 
= 2 L(t) + L(1)
L(1) = 
= (-1/s) ( 0 -1 )
= 1/s , ( s > 0)
2L ( t ) = 
= ![2[t\int\limits^\infty_0 e^{-st} - \int\limits^\infty_0 ({(d/dt)(t) \int\limits^\infty_0e^{-st} \, dt )dt]](https://tex.z-dn.net/?f=2%5Bt%5Cint%5Climits%5E%5Cinfty_0%20e%5E%7B-st%7D%20-%20%5Cint%5Climits%5E%5Cinfty_0%20%28%7B%28d%2Fdt%29%28t%29%20%5Cint%5Climits%5E%5Cinfty_0e%5E%7B-st%7D%20%5C%2C%20dt%20%29dt%5D)
= 2/ s²
Now ,
L(f(t))s = 2 L(t) + L(1)
= 2/ s² + 1/s
Therefore, the solution of the given function using Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].
Learn more about Laplace transform here
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Answer:
7.2
Step-by-step explanation:
Do 6^2 = 36
Do 4^2 = 16
Add them which equal 52
Square root of 52 is 7.2 to 1 decimal Place this is a possible length
The amount Howie need to pay back at the end of one year, including the interest is $26,000
Given:
Interest rate = 4%
Cost of car = $25,000
Time = 1 year
<em>Amount of interest</em> = Principal × Rate × Time
= 25,000 × 4% × 1
= 25,000 × 0.04 × 1
= $1,000
<em>Amount to be paid </em>= Amount of interest + Cost of car
= 1,000 + 25,000
= $26,000
Therefore, the amount Howie need to pay back at the end of one year, including the interest is $26,000
Learn more about interest rate:
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Answer:
c
Step-by-step explanation:
