Continental glaciers have depressed the crust below them true or false

Using the reaction below, identify the species that re acting as acids , as described by Bronstead-Lowry. HBO3-2(aq) + H2PO4-(aq

inessss [21]

Acids: $\text{H}_{2}\text{PO}_{4}^{\text{ }-}$ and $\text{H}_{2}\text{BO}_{3}^{\text{ } -}$

Bases: $\text{HBO}_{3}^{\text{ } 2-}$ and $\text{HPO}_{4}^{\text{ } 2-}$

4 0

2 years ago

Helium is mixed with oxygen gas for deep-sea divers. Calculate the percent by volume of oxygen gas in the mixture if the diver h

kvasek [131]

Answer : The percent by volume of oxygen gas in the mixture is, 5.3 %

Explanation :

According to the Raoult's law,

$p^o_A=X_A\times p_A$

where,

$p_A$ = total partial pressure of solution = 3.8 atm

$p^o_A$ = partial pressure of oxygen = 0.20 atm

$X_A$ = mole fraction of oxygen = ?

Now put all the given values in this formula, we get:

$p^o_A=X_A\times p_A$

$0.20atm=X_A\times 3.8atm$

$X_A=0.0526$

Now we have to calculate the percent by volume of oxygen gas in the mixture.

The mole percent of oxygen gas = $0.0526\times 100=5.3\%$

As we know that, there is a direct relation between the volume of moles.

So, mole percent of oxygen gas = volume percent of oxygen gas

Volume percent of oxygen gas = $0.0526\times 100=5.3\%$

Therefore, the percent by volume of oxygen gas in the mixture is, 5.3 %

5 0

4 years ago

Plz, HELP ME!!!

Dafna1 [17]

Thermometer with black bulb because black reflects less heat than white

4 0

3 years ago

Read 2 more answers

Use the ideal gas law to calculate the pressure in atmospheres of 0.21 mol of helium (He) at 16°C & occupying 2.53 L. You mu

chubhunter [2.5K]

Answer:

The answer to your question is 2.32 atm

Explanation:

Data

P = ?

n = 0.214

V = 2.53 L

T = 61°C

R = 0.082 atm L/mol°K

Formula

PV = nTR

solve for P

P = nRT/V

Process

1.- Calculate the temperature in K

°K = °C + 273

°K = 61 + 273

= 334

2.- Substitution

P = (0.214 x 0.082 x 334) / 2.53

3.- Simplification

P = 5.86/2.53

4.- Result

P = 2.32 atm

4 0

3 years ago

a man bought two watches for Rs 2500 each.He sold one of them at 10% . profit and the other at 4% loss.what was his gain or loss

timofeeve [1]

Answer:

Selling price of watch A and watch B= Rs. 425

Let cost price of watch A=x

Profit =10%

∴

100

110

x=425

x=386.36

Let cost price of watch B=y

Loss =10%

∴

100

90

y=425

y=472.22

Net cost price =x+y=858.5858

Net selling price =850

Loss%=

858.58

858.5858−850

×100=1%

Explanation:

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5 0

3 years ago