Answer:
B.
Explanation:
Some of the elements of the third-period and periods below can have expanded octet because they have d- sub-level.
We have 2 possible answers. A and B. Because lodine and chlorine. Sulfur and phosphorous are in the 3d or lower periods.
In the compound P2S5, where P forms 5 bonds.
Iodine and chlorine do not have enough difference in electronegativity to form compound ICl7.
So, the answer is B.
Answer:
Option D. 1×10¯¹⁰ M
Explanation:
From the question given above, the following data were obtained:
pH = 10
Hydrogen ion concentration, [H+] =?
The hydrogen ion concentration, [H+] of the Ba(OH)2 solution can be obtained as follow:
pH = – Log [H+]
pH = 10
10 = – Log [H+]
Divide both side by – 1
– 10 = Log [H+]
Take the antilog of – 10
[H+] = antilog (– 10)
[H+] = 1×10¯¹⁰ M
Therefore, the hydrogen ion concentration, [H+] of the Ba(OH)2 solution is 1×10¯¹⁰ M
Answer:
It is A
Explanation:
If you think about it, no-polar covalent bonds are in a symmetrical line, and polar bonds are on the diagonals of the center atom.
I hope I helped :)
it can with stand certain pressure inside, once it exceeds the pressure will be released by making a whistle....... hence it wont burst
Compounds are not possible to be separated by physical means
