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Natalka [10]
3 years ago
7

Problems of addition, subtraction, multiplication and division of integers for other people to solve.

Mathematics
1 answer:
kozerog [31]3 years ago
7 0
Yes i can do it almost anytime
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Please help me with question b) and please explain!!<br>look at the attached image
natta225 [31]

Answer:

17

Step-by-step explanation:

let x be the number of boxes to be shaded to make it 80%

x = 80% of total number

= 80/100 of 25

= 80/4

= 20

So 20 need to be shaded to fill 80%

Now, 13 of the grids are already shared so the amount of more squares that need to be shaded = 20-13

= 17 squares

4 0
3 years ago
Read 2 more answers
Pls answer you’ll get 100 points
Dahasolnce [82]

Take 2points

  • (0,0)
  • (3,2)

Equation in two point form

\\ \sf\longmapsto y-y_1=\left(\dfrac{y_2-y_1}{x_2-x_1}\right)x-x_1

\\ \sf\longmapsto y-0=\dfrac{2-0}{3-0}(x-0)

\\ \sf\longmapsto y=\dfrac{2}{3}x

.

Option D is correct

8 0
2 years ago
Read 2 more answers
Fernando invested money in a 5-yr CD (certificate of deposit) that returned the equivalent of 3.3% simple interest. He invested
iren [92.7K]

Answer:

Fernando invested $ 5000 on the 5-year CD and $ 4000 on the 18-month CD.

Step-by-step explanation:

Since Fernando invested money in a 5-yr CD (certificate of deposit) that returned the equivalent of 3.3% simple interest, and the invested $ 1000 less in a 18-month CD that had a 2% simple interest return, if the total amount of interest from these investments was $ 945.00, to determine how much was invested in each CD the following calculation must be performed:

3.3 x 5 = 16.5

2 x 1.5 = 3

4000 x 0.165 + 3000 x 0.03 = 750

6000 x 0.165 + 5000 x 0.03 = 1140

5000 x 0.165 + 4000 x 0.03 = 945

Therefore, Fernando invested $ 5000 on the 5-year CD and $ 4000 on the 18-month CD.

3 0
2 years ago
In a quadrilateral ABCD, AB ∥ DC and AD ∥ BC . Find the perimeter of ΔCOD if the diagonals of the quadrilateral intersect each o
SVEN [57.7K]

Answer Perimeter = 33in

Step-by-step explanation:

AC = 20

BD = 20

AB = 13

O is the midpoint

OD = OC = 20/2 = 10

AB = DC = 13 in

P = DC + OD + OC = 13+10+10 = 33in

5 0
2 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,
klasskru [66]

Given:

The scale factor is s=\dfrac{1}{3} and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

Solution:

Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

According to the given information, the scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

5 0
2 years ago
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