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MissTica
3 years ago
5

Radials are weird

qrt{6}) ^{2} " alt="(14 \sqrt{6}) ^{2} " align="absmiddle" class="latex-formula">whats the answer and how do i solve pls
Mathematics
1 answer:
MAVERICK [17]3 years ago
3 0

Answer:

  1,176

Step-by-step explanation:

An exponent is a way to represent repeated multiplication. That is ...

  x² = x·x . . . . . . . the exponent of 2 means x is a factor 2 times in the product

So, your expression means ...

  (14√6)² = (14·√6)·(14·√6)

Of course, the commutative and associative properties of multiplication allow us to regroup these factors to some convenient order, such as ...

  (14·14)·(√6)(√6) = 196·(√6)(√6)

We know that multiplying a square root times itself gives the original number. (This is the whole point of a square root.) That is ...

  (√6)(√6) = 6

So, the product above is ...

  (14√6)² = 14·14·(√6)(√6) = 196·6 = 1,176

_____

Since there are no variables involved here, your calculator can give you this answer.

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romanna [79]

Answer:From the attached graphic, Half-life = ln (.5) / k

Half-life =.693147 / 0.1142

= 6.0695884413 days

Step-by-step explanation:The value of "k" should be negative and should have units associated with it.

3 0
3 years ago
For each equation below find y if x = 2
Charra [1.4K]
A.
y = 7 - |x| = 7 - 2 = 5

b.
y = x² - 1 = 2² - 1 = 4 - 1 = 3

c.
y = √(x + 14) = √(2 + 14) = √16 = 4
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3 years ago
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A dataset lists full IQ scores for a random sample of subjects with low lead levels in their blood (sample 1) and another random
Alenkasestr [34]

Answer:

a. Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 >\mu_2

b. t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282

c. p_v =P(t_{97}>2.287) =0.0122

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).  

Step-by-step explanation:

a. State and label the null and alternative hypotheses.

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 >\mu_2

Or equivalently:

Null hypothesis: \mu_1 - \mu_2 \leq 0

Alternative hypothesis: \mu_1 -\mu_2>0

Our notation on this case :

n_1 =78 represent the sample size for group 1

n_2 =21 represent the sample size for group 2

\bar X_1 =92.88 represent the sample mean for the group 1

\bar X_2 =86.90 represent the sample mean for the group 2

s_1=15.34 represent the sample standard deviation for group 1

s_2=8.99 represent the sample standard deviation for group 2

b. State the value of the test statistic.

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{s^2_2}{n_2}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom. If we replace the values given we have:

t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282

Now we can calculate the degrees of freedom given by:

df=78+21-2=97

c. Find either the critical value(s) and draw a picture of the critical region(s) or find the P-value for this test. Indicate which method you are using: ( CIRCLE ONE: Critical value / P-value )

Method used: P value

And now we can calculate the p value using the altenative hypothesis, since it's a right tail test the p value is given by:

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So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).  

6 0
3 years ago
The length and width of a rectangle are 7 cm and (x-8) cm respectively. Find the value of x if the area of the rectangle is 42 c
soldi70 [24.7K]
Given length l=7
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Ede4ka [16]

Answer:

The next number is 1321232112

Step-by-step explanation:

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1312 is read off as "one 1, one 3, one 1, one 2" = 11131112

11131112 is read off as "three 1s, one 3, three 1s, one 2" = 31133112

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