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Ok? what's the rest, u can't solve unless there's a question like : how many hours does he have to work in order to go on vacation, I'm sorry but u make no sense
Coordinates : A(1,2) B(-5,6) C(7,-4) D(-2,t) - All are taken in order
gradient of AB = (6-2)/(-5-1) = 4/-6 = -⅔
since it is quadrilateral, AB//CD
gradient of CD = -⅔
equation of CD : y-(-4)=-⅔(x-7)
y+4=-⅔x+14/3
y=-⅔x+⅔
now, sub x=-2 from D(-2,t)
since t is the y-coordinate of point D
t=-⅔(-2)+⅔
t=2
Therefore, t=2
Answer:

Step-by-step explanation:
So we need to find an equation of a line that crosses the point (6,-4) and is perpendicular to y = -2x -3.
First, let's find the slope of the line we want to write. The line we want is perpendicular to y = -2x -3. Recall that if two lines are perpendicular to each other, their slopes are negative reciprocals of each other. What this means is that:

Plug -2 for one of the slopes.

Divide by -2 to find the slope of our line.

Thus, our line needs to have a slope of 1/2.
Now, let's use the point-slope form. The point-slope form is given by:

Plug in 1/2 for the slope m and let's let our point (6,-4) be x₁ and y₁. Thus:

Simplify and distribute:

Subtract 4 from both sides:

The above is the equation that passes the point (6,-4) and is perpendicular to y = -2x -3.
Answer:
um 2x dos
Step-by-step explanation: