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inn [45]
3 years ago
14

in Texas, a city that is far inland is typically cooler and drier than a city near the Gulf of Mexico. Agree or disagree. why?

Chemistry
1 answer:
Snezhnost [94]3 years ago
6 0

Answer:

Disagree

Explanation:

The water has a certain property i.e it has a high heat carrying capacity, as a result of which the water in the oceans are heated at a much slower rate.

On the other hand, the land areas absorbs a huge amount of incoming solar radiation, as a result of which it gets heated up at a much a faster rate.

So, the places that are near the seas and oceans remains cooler than the places that are far away. According to the given condition, the cities that are far inland are much warmer and moist compared to the cities that are located near the Gulf of Mexico.

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How many moles of oxygen are present in 33.6l of the gas at 1atm and 0c
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The answer is: 1.5 moles of oxygen are present.

V(O₂) = 33.6 L; volume of oxygen.

p(O₂) = 1.0 atm; pressure of oxygen.

T = 0°C; temperature.

Vm = 22.4 L/mol; molar volume at STP (Standard Temperature and Pressure).

At STP one mole of gas occupies 22.4 liters of volume.

n(O₂) = V(O₂) ÷ Vm.

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n(O₂) = 1.50 mol; amount of oxygen.

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The heat of fusion AH, of ethyl acetate (C4H802) is 10.5 kinol. Calculate the change in entropy as when 398. g of ethy, acetate
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<u>Answer:</u> The entropy change of the ethyl acetate is 133. J/K

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethyl acetate = 398 g

Molar mass of ethyl acetate = 88.11 g/mol

Putting values in above equation, we get:

\text{Moles of ethyl acetate}=\frac{398g}{88.11g/mol}=4.52mol

To calculate the entropy change for different phase at same temperature, we use the equation:

\Delta S=n\times \frac{\Delta H_{fusion}}{T}

where,  

\Delta S = Entropy change  = ?

n = moles of ethyl acetate = 4.52 moles

\Delta H_{fusion} = enthalpy of fusion = 10.5 kJ/mol = 10500 J/mol   (Conversion factor:  1 kJ = 1000 J)

T = temperature of the system = 84.0^oC=[84+273]K=357K

Putting values in above equation, we get:

\Delta S=\frac{4.52mol\times 10500J/mol}{357K}\\\\\Delta S=132.9J/K

Hence, the entropy change of the ethyl acetate is 133. J/K

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