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kupik [55]
3 years ago
5

16. Chemists can synthesize new materials using

Chemistry
1 answer:
Alex787 [66]3 years ago
8 0

Answer:

Yes Concurred,but where is the question

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Which of the following atoms has the largest atomic radius? Provide an explanation
trapecia [35]

Answer:

d Rubidium

Explanation:

The atomic radius of an atom is the distance from the center of the nucleus to its outermost electron.

The atomic radius of elements varies in the periodic table, it increases as you go down in a group and decreases along the period from left to right.  

All the elements listed: Hydrogen, Sodium, Lithium and Rubidium belong to the same group in the periodic table (group 1), Since atomic radius increases from top to bottom in a group, Rubidium has the largest atomic radius.

4 0
3 years ago
I searched it up but it keeps saying chemical energy, but in the option doesn’t have it...I’m torn between B and C...helppppp!!!
jeyben [28]

Answer: The correct answer is in chemical bonds

Explanation:

When coal is burnt, these components burn and release energy. The energy released is by the chemical reaction between the constituents and oxygen

8 0
3 years ago
Electrons are found in energy levels around the nucleus of an atom. Energy levels can also be called ""shells."" The energy leve
melamori03 [73]

Answer:

<u>The first electronic shell or energy level, having n= 1, called the K shell, is the closest to the nucleus.</u>

Explanation:

In an atom, the sub atomic particles called electrons, revolve around the nucleus of the given atom at different <em>energy levels</em>, called <em>shells</em>.

The energy levels or the electronic shells are denoted by the <em>principal quantum number</em>  <em>(n)</em> and has the following values n = 1, 2, 3, 4, 5, 6, 7; <em>from the innermost shell to the outermost.</em>

The electron shells are also labelled by the alphabets, K, L, M, N, O, P, and Q, <em>from the innermost shell to the outermost.</em>

<u><em>Thus the first electronic shell having n= 1, called K shell, is the lowest energy level and is present closest to the nucleus.</em></u>

<u><em>Whereas, the last electronic shell having n =7, called Q shell, is the highest energy level and is farthest from the nucleus.</em></u><u> </u>

5 0
3 years ago
Help I don’t understand it and I need the answers
il63 [147K]

Answer:

Demonstration 1 showed a chemical change because a new gaseous substance was formed, and demonstration 2 showed a physical change because liquid water became water vapor.

Explanation:

Chemical changes alter the chemical makeup of a subject, and a physical change only alters the appearance of a subject, not the chemical makeup.

4 0
3 years ago
If 12.5 grams of strontium hydroxide is reacted with 150 mL of 3.5 M carbonic acid, identify the limiting reactant.
vesna_86 [32]

Answer:

Sr(OH)2

Explanation:

We'll begin by calculating the number of mole of carbonic acid in 150mL of 3.5 M carbonic acid solution. This is illustrated below:

Molarity = 3.5M

Volume = 150mL = 150/1000 = 0.15L

Mole of carbonic acid, H2CO3 =..?

Mole = Molarity x Volume

Mole of carbonic acid, H2CO3 = 3.5 x 0.15 = 0.525 mole.

Next, we shall convert 0.525 mole of carbonic acid, H2CO3 to grams.

Mole of H2CO3 = 0.525 mole

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 =..?

Mass = mole x molar mass

Mass of H2CO3 = 0.525 x 62 = 32.55g

Next, we shall write the balanced equation for the reaction. This is given below:

Sr(OH)2 + H2CO3 → SrCO3 + 2H2O

Next, we shall determine the mass of Sr(OH)2 and H2CO3 that reacted from the balanced equation. This is illustrated below:

Molar mass of Sr(OH)2 = 88 + 2(16 + 1) = 88 + 2(17) = 122g/mol

Mass of Sr(OH)2 from the balanced equation = 1 x 122 = 122g

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 from the balanced equation = 1 x 62 = 62g.

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Finally, we shall determine the limiting reactant as follow:

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Therefore, 12.5g of Sr(OH)2 will react with = (12.5 x 62)/122 = 6.35g.

We can see evidently from the calculations made above that it will take 6.35g out 32.55g of H2CO3 to react with 12.5g of Sr(OH)2. Therefore, Sr(OH)2 is the limiting reactant and H2CO3 is the excess reactant

5 0
3 years ago
Read 2 more answers
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