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gtnhenbr [62]
3 years ago
7

Equilibrium is established between a liquid and its vapor when A. the rate of evaporation equals the rate of condensation. B. eq

ual masses exist in the liquid and gas phases. C. equal concentrations (in molarity) exist in the liquid and gas phases. D. all the liquid has evaporated. E. the liquid ceases to evaporate and the gas ceases to condense.
Chemistry
1 answer:
Advocard [28]3 years ago
6 0

Answer:

A

Explanation:

the rate of evaporation equals the rate of condensation.

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How many grams of lead(II) iodide are produced from 6.000 moles of NaI according to the balanced equation: Pb(NO3)2 + 2 NaI à 2
marta [7]

Answer:

mass PbI₂ formed = 1383 grams

Explanation:

Pb(NO₃)₂ + 2NaI => 2NaNO₃ + PbI₂(s)

6 mol NaI =>  1/2(6 mol) PbI₂ = 3 mol PbI₂ x 461.01 g/mol = 1383.03 grams ≅ 1383 grams (4 sig. figs.)

7 0
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HURRRYYY <br> in a chemical reaction you will always have an excess reactant. true or false?
just olya [345]

Answer:

It's False

Explanation:

In a chemical reaction, reactants that are not used up when the reaction is finished are called excess reagents. The reagent that is completely used up or reacted is called the limiting reagent, because its quantity limits the amount of products formed.

Hope this helps you

8 0
3 years ago
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Which of the following steps will slow down the reaction between coal and oxygen?
irakobra [83]

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decrease temperature of the oxygen

Explanation:

5 0
3 years ago
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How many molecules are in 20,484 grams of H2O?​
alexandr1967 [171]

Answer:

3.4027x10^-22

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4 0
3 years ago
When 15.3 g of sodium nitrate, NaNO3,was dissolved in water in a calorimeter, the temperature fell from 25.00oC to 21.56oC. If t
satela [25.4K]

Answer:

20.468 kilo Joules is the enthalpy change when one mole of sodium nitrate dissolves.

Explanation:

Heat lost by solution ad calorimeter = Q

Heat capacity of solution ad calorimeter = C = 1071 J/°C

Change in temperature = ΔT = 21.56°C - 25.00°C = -3.44°C

Q=C\times Delta T

Q=1071 J/^oC\times (-3.44^oC)=-3,684.24 J

Heat gained by sodium nitrate = -Q = -(-3,684.24 J)=3,684.24 J

Moles of sodium nitrate = \frac{15.3 g}{85 g/mol}=0.18 mol

When 0.18 mole of sodium nitrate was dissolved in water 3,684.24 joulesof heat was absorbed by it.

Then heat absorbed by 1 mole of sodium nitrate :

\frac{3,684.24 J}{0.18}=20,468 J=20.468 kJ

1 J = 0.001 kJ

20.468 kilo Joules is the enthalpy change when one mole of sodium nitrate dissolves.

8 0
3 years ago
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