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kobusy [5.1K]
3 years ago
15

Find the distance between the points (3, –8) and (0, –9).

Mathematics
1 answer:
nadezda [96]3 years ago
4 0

The formula for distance between two points is:

\sqrt{(x_{2} -x_{1})^{2} + (y_{2} -y_{1})^{2}}

In this case:

x_{2} =0\\x_{1} =3\\y_{2} =-9\\y_{1} =-8

^^^Plug these numbers into the formula for distance like so...

\sqrt{(0-3)^{2} + (-9 - (-8))^{2}}

To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

First we have parentheses. Remember that when solving you must go from left to right

\sqrt{(0-3)^{2} + (-9-(-8))^{2}}

0 - 3 = -3

\sqrt{(-3)^{2} + (-9-(-8))^{2}}

-9 - (-8) = -1

\sqrt{(-3)^{2} + (-1)^{2}}

Next solve the exponent. Again, you must do this from left to right

\sqrt{(-3)^{2} + (-1)^{2}}

(-3)² = 9

\sqrt{9 + (-1)^{2}}

(-1)² = 1

\sqrt{(9+1)}

Now for the addition

\sqrt{(9+1)}

9 + 1 = 10

√10 <<<This can not be further simplified so this is your exact answer

Your approximate answer would be about 3.16

***Remember that the above answers are in terms of units

Hope this helped!

~Just a girl in love with Shawn Mendes

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A sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to
Archy [21]

Answer:

0.2916, 0.1488, 0.0319

Step-by-step explanation:

Given that a sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to have oil added.

Since each trial is independent there is a constant probability for any random car to need oil is 0.10

Let X be the number of cars that need oil

A) Here X is BIN(4,0.1)

P(X=1) = 4C1(0.1)(0.9)^3 \\= 0.2916

B) Here X is Bin (8, 0.1)

P(x=2) = 8C2 (0.1)^2 (0.9)^6\\\\=0.1488

C) Here X is Bin (20,5)

P(x=5) = 20C5 (0.1)^5 (0.9)^{15} \\=0.0319

3 0
3 years ago
F(x)=2x^2 -5 , simplify f(x+h)/h , where h≠0
7nadin3 [17]

Answer:

\huge\boxed{\dfrac{f(x+h)}{h}=\dfrac{2x^2+4xh+2h^2-5}{h}}

\huge\boxed{\dfrac{f(x+h)}{h}=\dfrac{2x^2-5}{h}+4x+2h}

Step-by-step explanation:

f(x)=2x^2-5\\\\\dfrac{f(x+h)}{h}=\dfrac{2(x+h)^2-5}{h}=\dfrac{2(x^2+2xh+h^2)-5}{h}\\\\\dfrac{f(x+h)}{h}=\dfrac{2x^2+4xh+2h^2-5}{h}\\\\h\neq0

4 0
3 years ago
What is the domain in interval notation?
Sonbull [250]

Answer:

The answers are all real numbers where x<2 or x>2. We can use a symbol known as the union, ∪,to combine the two sets. In interval notation, we write the solution:(−∞,2)∪(2,∞). In interval form, the domain of f is (−∞,2)∪(2,∞).

8 0
3 years ago
D = 18 in. Fine the radius or diameter of each circle with the given dimensions. ​
Alborosie

Answer:

r= 9

Step-by-step explanation:

radius (r) = diameter (D)/2

= 18/2

= 9

4 0
3 years ago
Please help me out with this math problem
Novosadov [1.4K]
Answer: 74.8%

This answer is approximate.
The value is rounded to the nearest tenth of a percent.

==========================================

Explanation:

Let,
X = area of the larger circle
Y = area of the smaller circle
Z = area of the shaded region = X - Y

The goal is to compute the ratio Z/X to get the answer we want

Let's find area of the larger circle
Area of circle = pi*(radius)^2
A = pi*r^2
X = pi*8.01^2
X = 64.1601pi
This is the exact area in terms of pi

Now repeat for the smaller circle
A = pi*r^2
Y = pi*4.02^2
Y = 16.1604pi

Subtract those results to find the value of Z
Z = X-Y
Z = 64.1601pi-16.1604pi
Z = 47.9997pi
This is the exact area of the red donut region

Divide Z over X to get the probability of landing in the red region
Z/X = (47.9997pi)/(64.1601pi)
Z/X = (47.9997)/(64.1601) <--- note how the pi terms cancel
Z/X = 0.74812 which is approximate

Convert to a percent
Move the decimal point 2 spots to the right
0.74812 ---> 74.812%

Then round this to one decimal place
74.812% ---> 74.8%

5 0
3 years ago
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