The answer is C 24 if you plug in 33 33 = 9 + b you have to subtract the 9 over to 33 to get 24
Answer:
2
Step-by-step explanation:
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A. <u>False.</u> The range of
is the set of values it can produce. In the table,
produces values from
to
. However, the range of all real numbers is all rational numbers, basically from
to
, not just a few numbers in-between. So, the range of
is not all real numbers.
B. <u>True.</u> Looking at the table, when
,
. This is another way of saying that
, which is what B is saying.
C. <u>True.</u> The domain of
is the set of values of
that produce some output in
. Looking at the table, all of the
values listed on it are in the set
, which is what C is saying.
D. <u>False.</u> Looking at the table, when
,
. This is another way of saying that
, which is <em>not </em>what B is saying.
Answer:
Step-by-step explanation:
![x^4+4x^3-27x-108\\=x^3(x+4)-27(x+4)\\=(x+4)(x^3-27)\\=(x+4)[x^3-3^3]\\=(x+4)(x-3)(x^2+3x+3)](https://tex.z-dn.net/?f=x%5E4%2B4x%5E3-27x-108%5C%5C%3Dx%5E3%28x%2B4%29-27%28x%2B4%29%5C%5C%3D%28x%2B4%29%28x%5E3-27%29%5C%5C%3D%28x%2B4%29%5Bx%5E3-3%5E3%5D%5C%5C%3D%28x%2B4%29%28x-3%29%28x%5E2%2B3x%2B3%29)
For two triangles to be congruent, we need to show is two of the
1. corresponding angles are congruent,
or,
2. all three pairs of corresponding sides are proportional,
or
3. two pairs of corresponding sides are proportional AND the included angles are congruent.
Choice D saus, angles Q and Q' are congruent, angles R and R' are congruent, therefore satisfies the first criterion that at least two corresponding angles are congruent.