Answer:
Option A
Option B
Option E
Option G
Option A and E go together
and
Option B and G go together.
Answer:
7/10
Step-by-step explanation:
Answer:
lj= lk din 30 give lj= 4✓2
and ml=x= lj cos 45
on solving x= 4✓2 cos45=4
Answer:x= 5/2 x= -1/2
Step-by-step explanation:
4(x-1)2-9
4(x2-2x+1) - 9
4x2 - 8x + 4 - 9
4x2 - 8x - 5
4x2 +2x - 10x - 5
2x(2x+1) - 5(2x+1)
(2x-5)(2x+1)
therefore, x= 5/2 x= -1/2
mark brainliest plzz
Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:
1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.
The total walkway area is thus x^2 + 4(2^2) + 4(x*2).
We want to find the dimensions of the garden. To do this, we need to find the value of x.
Let's sum up the garden dimensions and the walkway dimensions:
x^2 + 4(2^2) + 4(x*2) = 196 sq ft
x^2 + 16 + 8x = 196 sq ft
x^2 + 8x - 180 = 0
(x-10(x+18) = 0
x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.
The garden dimensions are (10 feet)^2, or 100 square feet.
