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Harlamova29_29 [7]
3 years ago
7

Two liquids A and B have boiling points 350 k and 375 k respectively. Which of the two has greater intermolecular forces of attr

action ?
Chemistry
1 answer:
kirill [66]3 years ago
3 0
Hello, I am Emac or Eric.

I will be assisting you, today. Thanks for posting this, I have been reviewing and have found some information that hopefully gets you to your answer!

Please press the thanks button if this helps so I KNOW I helped someone out, if not please reply why. I will reply when I get a chance.

NOW to the answer. Here is some information!





All other factors being equal, the liquid with the higher boiling point will be the substance whose molecular force of attraction is greater. Think of it this way, the greater the molecular force of ATTRACTION, the more energy it takes to SEPARATE the molecules by a greater distance and move the substance from the liquid state to the vapor state. Cheers!

Please reply for more questions if needed!

Have a great day/night!

Emacathy,
Brainly Team.
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Which would melt first, the element
balandron [24]

Explanation:

First, get both values into the same units

To covert from Kelvin to degrees C, subtract 273.15

1210 - 273.15 =936.85

Melting point of germanium=936.85 degrees C

Melting point of gold= 1064 degrees C

Therefore germanium would melt first because it has the lower melting point.

4 0
3 years ago
Given the following equation: 4 NH3 (g)5 O2 (g) >4 NO (g) + 6 H20 (I) How many moles of NH3 is required to react with 25.7 gr
Sergeu [11.5K]

Answer:

0.6425 moles of NH_3 is required to react with 25.7 grams of O_2.

Explanation:

mas of oxygen gas = 25.7 g

moles of oxygengas = \frac{25.7 g}{32 g/mol}=0.8031 mol

4NH_3 (g)+5O_2 (g) \rightarrow 4 NO(g) + 6H_20 (I)

According to reaction given above,  5 moles of oxygen gas reacts with 4 moles of ammonia gas.

Then 0.8031 moles of oxygen gas will react with :

\frac{4}{5}\times 0.8031 mol=0.6425 mol of ammonia gas

0.6425 moles of NH_3 is required to react with 25.7 grams of O_2.

5 0
3 years ago
Write a balanced chemical equation for the decomposition of RbNO3.<br><br>Help me please!!!​
nalin [4]

Answer:

<u>2RbNO³ --> 2Rb + N² + 30²</u>

Hope this helps!

8 0
3 years ago
What is the density of an object with a mass of 10 g and a volume of 2 cm3?
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What is the mass of H2O produced when 10.0 grams of H2 reacts completely with 80.0 grams of O2?
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H₂:

M=2g/mol
m=10g

n = m/M = 10g/2g/mol = 5mol

O₂:

M = 32g/mol
m = 80g

n = m/M = 80g/32g/mol = 2,5mol

2H₂        +            O₂          ⇒          2H₂O
2mol            :       1mol        :          2mol
5mol            :       2,5mol     :          5mol
10g              :       80g           :         10g+80g=90g

B
8 0
3 years ago
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