Answer:
which following give options
The atomic mass of X₁ is 14 and the name of the element is Nitrogen.
The atomic mass of X₂ is 16 and the name of the element is Oxygen.
The atomic mass of X₃ is 32 and the name of the element is Sulfur.
The given parameters include:
weight C weight X
Compound 1 4.2 4.9
Compound 2 3.5 4.67
Compound 3 1.3 3.47
The atomic mass of the first compound (X₁) is calculated as follow;
let the total mass of X₁ and C = T
X₁ + C = T
![\frac{weight \ of \ C}{total \ weight } \times total \ atomic \ mass = mass \ of \ C \\\\\frac{4.2}{(4.2 + 4.9)} \times T = 12\\\\4.2 T = 12(9.1)\\\\4.2T = 109.2\\\\T = \frac{109.2}{4.2} \\\\T = 26](https://tex.z-dn.net/?f=%5Cfrac%7Bweight%20%5C%20of%20%5C%20C%7D%7Btotal%20%5C%20weight%20%7D%20%5Ctimes%20total%20%5C%20atomic%20%5C%20mass%20%3D%20mass%20%5C%20of%20%5C%20C%20%20%5C%5C%5C%5C%5Cfrac%7B4.2%7D%7B%284.2%20%2B%204.9%29%7D%20%5Ctimes%20T%20%3D%2012%5C%5C%5C%5C4.2%20T%20%3D%2012%289.1%29%5C%5C%5C%5C4.2T%20%3D%20109.2%5C%5C%5C%5CT%20%3D%20%5Cfrac%7B109.2%7D%7B4.2%7D%20%5C%5C%5C%5CT%20%3D%2026)
X₁ + C = T
X₁ + 12 = 26
X₁ = 26 - 12
X₁ = 14
The atomic mass of X₁ is 14 and the name of the element is Nitrogen.
The atomic mass of the second compound (X₂) is calculated as follow;
let the total mass = P
![\frac{3.5}{(3.5+4.67)} \times P = 12\\\\3.5P = 12 (8.17)\\\\3.5P = 98.04\\\\P = \frac{98.04}{3.5} \\\\P = 28](https://tex.z-dn.net/?f=%5Cfrac%7B3.5%7D%7B%283.5%2B4.67%29%7D%20%5Ctimes%20P%20%3D%2012%5C%5C%5C%5C3.5P%20%3D%2012%20%288.17%29%5C%5C%5C%5C3.5P%20%3D%2098.04%5C%5C%5C%5CP%20%3D%20%5Cfrac%7B98.04%7D%7B3.5%7D%20%5C%5C%5C%5CP%20%3D%2028)
![X_2 + C = P\\\\X_2 + 12 = 28\\\\X_2 = 28-12\\\\X_2 = 16](https://tex.z-dn.net/?f=X_2%20%2B%20C%20%3D%20P%5C%5C%5C%5CX_2%20%2B%2012%20%3D%2028%5C%5C%5C%5CX_2%20%3D%2028-12%5C%5C%5C%5CX_2%20%3D%2016)
The atomic mass of X₂ is 16 and the name of the element is Oxygen.
The atomic mass of the third compound (X₃) is calculated as follow;
Let the total mass = y
![\frac{1.3}{(1.3+3.47)} \times y = 12\\\\1.3y = 12 (4.77)\\\\1.3y = 57.24\\\\y = \frac{57.24}{1.3} \\\\y = 44](https://tex.z-dn.net/?f=%5Cfrac%7B1.3%7D%7B%281.3%2B3.47%29%7D%20%5Ctimes%20y%20%3D%2012%5C%5C%5C%5C1.3y%20%3D%2012%20%284.77%29%5C%5C%5C%5C1.3y%20%3D%2057.24%5C%5C%5C%5Cy%20%3D%20%5Cfrac%7B57.24%7D%7B1.3%7D%20%5C%5C%5C%5Cy%20%3D%2044)
![X_3 + C =y\\\\X_3 + 12 = 44\\\\X_3 = 44-12\\\\X_3 = 32](https://tex.z-dn.net/?f=X_3%20%2B%20C%20%3Dy%5C%5C%5C%5CX_3%20%2B%2012%20%3D%2044%5C%5C%5C%5CX_3%20%3D%2044-12%5C%5C%5C%5CX_3%20%3D%2032)
The atomic mass of X₃ is 32 and the name of the element is Sulfur.
Learn more here: brainly.com/question/13648441
Answer:
6.0×10_10=50 I hope I'm right
Answer:
Physical change: A,C ,D, F, H, I
Chemical Change: B, E, G, J, K
The correct answer for the question that is being presented above is this one: "FALSE." The carbon cycle involves an exchange of carbon between the atmosphere and geosphere only. This statement is false -- as well as the geosphere, the carbon cycle also moves carbon between the atmosphere, the biosphere, and the hydrosphere.