Answer:
Do research on a Particular topic
Answer:
8.37 grams
Explanation:
The balanced chemical equation is:
C₆H₁₂O₆ ⇒ 2 C₂H₅OH (l) + 2 CO₂ (g)
Now we are asked to calculate the mass of glucose required to produce 2.25 L CO₂ at 1atm and 295 K.
From the ideal gas law we can determine the number of moles that the 2.25 L represent.
From there we will use the stoichiometry of the reaction to determine the moles of glucose which knowing the molar mass can be converted to mass.
PV = nRT ⇒ n = PV/RT
n= 1 atm x 2.25 L / ( 0.08205 Latm/kmol x 295 K ) =0.093 mol CO₂
Moles glucose required:
0.093 mol CO₂ x ( 1 mol C₆H₁₂O₆ / 2 mol CO₂ ) = 0.046 mol C₆H₁₂O₆
The molar mass of glucose is 180.16 g/mol, then the mass required is
0.046 mol x 180.16 g/mol = 8.37 g
Answer:
The answer to your question is pH = 6.3
Explanation:
Data
pH = ?
[H⁺] = 4.73 x 10⁻⁷ M
pH is the measure of the concentration of [H⁺]. pH measures the acidity of the solution. If the value of pH is between 0 and 6.9, the solution is an acid. If the pH is 7.0 the solution is neutral and if the pH is between 7.1 and 14, the solution is an alkali.
Formula
pH = -log[H⁺]
Substitution
pH = -log[4.73 x 10⁻⁷]
-Simplification
pH = - (-6.3)
-Result
pH = 6.3
The volume of 0.20 moles of helium at STP is 4.5 liters.
Explanation:
Given:
Number of moles = 0.20 moles
To Find:
The volume of Helium at STP =?
Solution:
According to ideal gas law
PV = nRT
where
P is pressure,
V is volume,
n is the number of moles
R is the gas constant, and
T is temperature in Kelvin.
The question already gives us the values for p and T
,because helium is at STP. This means that temperature is 273.15 K and pressure is 1 atm
.
We also already know the gas constant. In our case, we'll use the value of
0.08206 L atm/K mol since these units fit the units of our given values the best
On substituting these values we get
V = 4.5 Liters
Well you didn’t post any but I’m hoping that either plastic, lead, wood, glass, or paper, are an option.
