5 equals 5/1. Simple as that.
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<span><span> 5x2-23x=-26</span> </span>Two solutions were found :<span><span> x = 2
</span><span> x = 13/5 = 2.600
</span></span>
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
5*x^2-23*x-(-26)=0
Step by step solution :Skip Ad
<span> Step 1 :</span><span>Equation at the end of step 1 :</span><span> (5x2 - 23x) - -26 = 0
</span><span> Step 2 :</span>Trying to factor by splitting the middle term
<span> 2.1 </span> Factoring <span> 5x2-23x+26</span>
The first term is, <span> <span>5x2</span> </span> its coefficient is <span> 5 </span>.
The middle term is, <span> -23x </span> its coefficient is <span> -23 </span>.
The last term, "the constant", is <span> +26 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> 5 • 26 = 130</span>
Step-2 : Find two factors of 130 whose sum equals the coefficient of the middle term, which is <span> -23 </span>.
<span><span>
-130
+
-1
=
-131
<span>
</span>
</span>
<span>
-65
+
-2
=
-67
<span>
</span>
</span>
<span>
-26
+
-5
=
-31
<span>
</span>
</span>
<span>
-13
+
-10
=
-23
That's it</span></span>
Answer:
See explanation and hopefully it answers your question.
Basically because the expression has a hole at x=3.
Step-by-step explanation:
Let h(x)=( x^2-k ) / ( hx-15 )
This function, h, has a hole in the curve at hx-15=0 if it also makes the numerator 0 for the same x value.
Solving for x in that equation:
Adding 15 on both sides:
hx=15
Dividing both sides by h:
x=15/h
For it be a hole, you also must have the numerator is zero at x=15/h.
x^2-k=0 at x=15/h gives:
(15/h)^2-k=0
225/h^2-k=0
k=225/h^2
So if we wanted to evaluate the following limit:
Lim x->15/h ( x^2-k ) / ( hx-15 )
Or
Lim x->15/h ( x^2-(225/h^2) ) / ( hx-15 ) you couldn't use direct substitution because of the hole at x=15/h.
We were ask to evaluate
Lim x->3 ( x^2-k ) / ( hx-15 )
Comparing the two limits h=5 and k=225/h^2=225/25=9.
