This response is based upon your having had some background in calculus. "dx" is not introduced before that.
Take a look at the sample function y = f(x) = x^2 + 9. Here x is the independent variable; the dependent variable y changes with x.
Now, for a big jump: we consider finding the area under a curve (graph) between x = a and x = b. We subdivide that interval [a,b] into n vertical slices of area. Each of those slices has its own area: f(x)*dx, where dx represents the width of such subarea. f(x)*dx is the actual subarea. To find the total area under the curve f(x) between x= a and x = b, we add up all of these individual subareas between x = a and x = b. Note that the subinterval width is
b-a
dx = ---------- , and that dx becomes smaller and smaller as the number of
n subintervals increases.
Once again, this all makes sense only if you've begun calculus (particularly integral calculus). Do not try to relate it to earlier math courses.
Answer:
35
Step-by-step explanation:
Given:
GH = 23
HR = 12
Required:
Length big QR
SOLUTION:
Since H is a point in between points Q and R, points Q, H, R are collinear.
QH = 23
HR = 12
QH + HR = QR (segment addition postulate)
23 + 12 = QR (substitution)
35 = QR
Therefore, the length of QR is 35
Answer:
The answer is B
Step-by-step explanation:
lol i had the same question
Answer:
The third option
Step-by-step explanation:
the most reasonable
Answer:
Volume of tennis ball = 11.49 inch³
Step-by-step explanation:
Given:
Radius of tennis ball = 1.4 inches
Value of π = 3.14
Find:
Volume of tennis ball
Computation:
Volume of sphere = [4/3][π][r]³
Volume of tennis ball = [4/3][π][Radius of tennis ball]³
Volume of tennis ball = [4/3][3.14][1.4]³
Volume of tennis ball = [1.333][3.14][1.4]³
Volume of tennis ball = [1.333][3.14][2.744]
Volume of tennis ball = [4.1856][2.744]
Volume of tennis ball = 11.4852
Volume of tennis ball = 11.49 inch³
