To factor this fraction, you have be be aware of two special factoring formula:
a^3<span> + </span>b^3<span> = (</span>a<span> + </span>b)(a^2<span> – </span>ab<span> + </span>b^2<span>)
</span><span>(a+b)³ = a³ + 3a²b + 3ab² + b³
You can see the top part in this case is (x+y)^3, and the bottom (denominator) can be factor into (x+y)(x^2-xy+y^2)
we can cancel (x+y), so what we have left is (x+y)^2/(x^2-xy+y^2)
or (x^2+2xy+y^2)/(x^2-xy+y^2)
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<h3>
Answer: 32</h3>
Explanation:
We add up the numbers found in the "math" circle
9+7+11+5 = 32
Answer:
Yes
6(x+0.4) is equivalent to 3(2x+0.8)
Step-by-step explanation:
Given in the questions two expressions
6(x + 0.4)
3(2x + 0.8)
We will apply distributive law
It is a law relating the operations of multiplication and addition, stated symbolically
<h3>a(b + c) = ab + ac</h3><h3 />
6(x + 0.4)
= 6(x) + 6(0.4)
= 6x + 2.4
3(2x + 0.8)
= 3(2x) + 3(0.8)
= 6x + 2.4
Since both equations when expanded have same answers, hence they are equivalent