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LuckyWell [14K]
3 years ago
14

Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true

standard deviation 0.79. (a) Compute a 95% CI for the true average porosity of a certain seam if the average porosity for 22 specimens from the seam was 4.85. (Round your answers to two decimal places.)
Mathematics
1 answer:
Nesterboy [21]3 years ago
8 0

Answer:

Interval=4.85±0.33

Interval (5.18,4.52)

Step-by-step explanation:

Consider the formula for the interval:

interval=X±\frac{Z*S}{\sqrt{n} }

Where:

X is the mean value

S is the standard deviation

n is the sample size

Z is the distribution

Alpha=1-0.95=0.05

Z_{alpha/2}=Z_{0.05/2} =Z_{0.025}=1.96 (From Standard Z-Distribution Table)

Now use the above formula

interval=4.85±\frac{1.96*0.79}{\sqrt{22} }

Interval=4.85±0.33

Interval (5.18,4.52)

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