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2 years ago

Alguien que me ayude con esto

Mathematics

1 answer:

pogonyaev2 years ago

7 0

Answer:

Triangulo: A= h(subindice b)b/2

Cuadrado: A= L×L o A=L^2

Rectangulo: A= b×a

Rombo: A= D×d/2

Romboide: A= b×h

Trapecio: A= (B×b)h/2

Trapezoide: A= b+B/2(h)

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HURRY!! NO SPAM!!!!!!!!!!!!!!!!!!

Zielflug [23.3K]

2moles of NaCl produced by 2 moles of NaClO_3
Let required moles be x .

$\\ \bull\sf\longmapsto 2:2=3:x$

$\\ \bull\sf\longmapsto \dfrac{2}{2}=\dfrac{3}{x}$

$\\ \bull\sf\longmapsto \dfrac{3}{x}=1$

$\\ \bull\sf\longmapsto x=3mol$

8 0

2 years ago

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Line Equation from Two Points

Verdich [7]

Hi!

We can use point-slope form to solve this.

$y-y_{1} =m(x -x_{1})$

$y_{1}$ and $x_{1}$ will be from one of the points.

First, we have to find $m$ , the slope. We can use the slope equation to get this.

$\frac{y_{1} -y_{2} }{x_{1} -x_{2} }$

Plug in your points:

$\frac{4-0}{8-(-8)} =\frac{4-0}{8+8} =\frac{4}{16} =\frac{1}{4}$

Your slope is $\frac{1}{4}$

Now plug points and slope into point-slope equation. We will use (8, 4).

$y-4=\frac{1}{4} (x-8)$

Now, if you want to get it into y = mx + b form, you have to solve for y:

$y-4=\frac{1}{4} (x-8)$

$y-4=\frac{1}{4} x-2$

$y=\frac{1}{4} +2$

Your equation is $y=\frac{1}{4} +2$

For more information on how to get the equation of a line when given two points, see here:

brainly.com/question/986503

7 0

2 years ago

Solve this problem please :)

zvonat [6]

The Answer is B 8/3 :)

4 0

2 years ago

Lalo has 1,500 minutes per month on his cell phone plan. How many more minutes can he use if he has already talked for 785 minut

emmainna [20.7K]

Answer:

All you have to do is subtract 1500-785 in order to find the number of minutes left for him.

1500-785=715 more minutes left

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3 years ago

Which statements about the area of the faces of the triangular prism are true? Select all that apply. Area of face A = 112 m2. A

ira [324]

Answer:

1,3,4

Step-by-step explanation:

all the others were wrong

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3 years ago

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Alguien que me ayude con esto​

Alguien que me ayude con esto