In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
I’m a bit confused by the choices you have been given. Are there any other options? If not, I would choose (5.3,9.8) as 9.8 is correct
Answer:
48*52=2496/2=1248
Step-by-step explanation:
Triangle syprine=b*h/2
16*14=224/2=112
answer b is the most similar:48*52=2496/2=1248
48 is 3x>16
Step-by-step explanation:
90 - 60 = 30
30 - 18 = 12
X=12
