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gregori [183]
3 years ago
9

Which of the following do Lewis structures help us understand?

Chemistry
2 answers:
kenny6666 [7]3 years ago
5 0
The correct answer is this one: "the number of electrons that are involved in the bonding of the molecule."  Lewis structures help us understand the number of electrons that are involved in the bonding of the molecule. It also helps us know the shape of the molecule, its reactivity and its interaction with other molecules.
Vadim26 [7]3 years ago
5 0

Answer: Option (b) is the correct answer.

Explanation:

A diagram which shows the number of electrons involved in bonding and number of lone pairs present on the atom(s) is known as a lewis structure.

The electrons in lewis structure are represented by dots.

Therefore, we can conclude that Lewis structures help us understand the number of electrons that are involved in the bonding of the molecule.

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In a chemical reaction, sulfur (S8) combines with copper to give a pure compound. If you start with 1.000 g of sulfur (S8) and o
Airida [17]

<u>Answer:</u> The empirical formula for the given compound is Cu_2S

<u>Explanation:</u>

We are given:

Mass of pure compound containing copper and sulfur = 4.963 g

Mass of S = 1.000 g

Mass of Cu = (4.963 - 1.000) g = 3.963 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Copper =\frac{\text{Given mass of Copper}}{\text{Molar mass of Copper}}=\frac{3.963g}{63.55g/mole}=0.0624moles

Moles of Sulfur = \frac{\text{Given mass of Sulfur}}{\text{Molar mass of Sulfur}}=\frac{1.000g}{32g/mole}=0.0312moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0312 moles.

For Copper = \frac{0.0624}{0.0312}=2

For Sulfur = \frac{0.0312}{0.0312}=1

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of Cu : S = 2 : 1

Hence, the empirical formula for the given compound is Cu_2S

8 0
3 years ago
Consider the Lewis structure for glycine, the simplest amino acid: (a) What are the approximate bond angles about each of the tw
UkoKoshka [18]

Each carbon is tetrahedrally planar and has three sections, making all bond angles in (a) 120°.(b) hybridization with sp2.(c) If a double bond is present in the compounds, one of the bonds is a sigma connection and the other a pi bond.

<h3>What is an example of an amino acid?</h3>

A basic amino group (NH2), a carboxyl group group (COOH), and an organic Aromatic rings that really is specific to each amino acid make up an amino acid, an organic molecule.

<h3>Which five amino acids are there?</h3>

You must obtain the nine essential amino acids cytochrome c, isoleucine, hcl, lysine, methionine, phenylalanine, alanine, tryptophan, and valine through your food.They are essential for several bodily processes, such as protein biosynthesis, tissue regeneration, and nutrient uptake.

To know more about Lewis structure visit:

brainly.com/question/20300458

#SPJ4

6 0
1 year ago
PLEASE HELP!!!!
castortr0y [4]

Answer:

B

IS THE CORRECT ANSWER

6 0
3 years ago
What is the molarity of a potassium triiodide solution, ki3(aq), if 30.00 ml of the solution is required to completely react wit
oee [108]

The molar concentration of the KI_3 solution is 0.0833 mol/L.

<em>Step 1</em>. Calculate the <em>moles of S_2O_3^(2-)</em>

Moles of S_2O_3^(2-) = 25.00 mL S_2O_3^(2-) ×[0.200 mmol S_2O_3^(2-)/(1 mL S_2O_3^(2-)] = 5.000 mmol S_2O_3^(2-)

<em>Step 2</em>. Calculate the <em>moles of I_3^(-) </em>

Moles of I_3^(-) = 5.000 mmol S_2O_3^(2-)))) × [1 mmol I_3^(-)/(2 mmol S_2O_3^(2-)] = 2.500 mmol I_3^(-)

<em>Step 3</em>. Calculate the <em>molar concentration of the I_3^(-)</em>

<em>c</em> = "moles"/"litres" = 2.500 mmol/30.00 mL = 0.083 33 mol/L

5 0
4 years ago
Read 2 more answers
Express the following as a whole number or as decimals: 3.5 x 10-3 m
ahrayia [7]
Multiply
10.3
by = 36.05m
3.5

.
7 0
3 years ago
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