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3 years ago

Etahnol has a density of 0.79 g/ml. what is the volume, in quarts, of 1.80 kg of alcohol?

Chemistry

1 answer:

xxTIMURxx [149]3 years ago

7 0

Density =mass /volume

Volume =1800÷0.79
= 2278.481ml

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5) Solid silver chloride, AgCl, precipitates when solution of silver nitrate, AgNO3, and iron (111) chloride,

DanielleElmas [232]

The chemical reaction between the reactants:

3 AgNO₃ (aq) + FeCl₃ (aq) → 3 AgCl (s) + Fe(NO₃)₃ (aq)

Explanation:

We have the following chemical reaction:

3 AgNO₃ (aq) + FeCl₃ (aq) → 3 AgCl (s) + Fe(NO₃)₃ (aq)

Complete ionic equation:

3 Ag⁺ (aq) + 3 NO₃⁻ (aq) + Fe³⁺ (aq) + 3 Cl⁻ (aq) → 3 AgCl (s) + Fe³⁺ (aq) + 3 NO₃⁻ (aq)

We remove the spectator ions and we get the net ionic equation:

Ag⁺ (aq) + Cl⁻ (aq) → AgCl (s)

where:

(aq) - aqueous

(s) - solid

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net ionic equation

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3 years ago

What would be the voltage (Ecell) of a voltaic cell comprised of Cr (s)/Cr3+(aq) and Fe (s)/Fe2+(aq) if the concentrations of th

zaharov [31]

Answer:

0.35 V

Explanation:

(a) Standard reduction potentials

E°/V

Fe²⁺ + 2e- ⇌ Fe; -0.41

Cr³⁺ + 3e⁻ ⇌ Cr; -0.74

(b) Standard cell potential

E°/V

2Cr³⁺ + 6e⁻ ⇌ 2Cr; +0.74

3Fe ⇌ 3Fe²⁺ + 6e-; -0.41

2Cr³⁺ + 3Fe ⇌ 2Cr + 3Fe²⁺; +0.33

3. Cell potential

2Cr³⁺(0.75 mol·L⁻¹) + 6e⁻ ⇌ 2Cr

3Fe ⇌ 3Fe²⁺(0.25 mol·L⁻¹) + 6e-

2Cr³⁺(0.75 mol·L⁻¹) + 3Fe ⇌ 2Cr + 3Fe²⁺(0.25 mol·L⁻¹)

The concentrations are not 1 mol·L⁻¹, so we must use the Nernst equation

$E = E^{\circ} - \dfrac{RT}{zF}\ln Q$

(a) Data

E° = 0.33 V

R = 8.314 J·K⁻¹mol⁻¹

T = 298 K

z = 6

F = 96 485 C/mol

(b) Calculations:

$Q = \dfrac{\text{[Fe}^{2+}]^{3}}{ \text{[Cr}^{3+}]^{2}} = \dfrac{0.25^{3}}{ 0.75^{2}} =\dfrac{0.0156}{0.562} = 0.0278\\\\E = 0.33 - \left (\dfrac{8.314 \times 298}{6 \times 96485}\right ) \ln(0.0278)\\\\=0.33 -0.00428 \times (-3.58) = 0.33 + 0.0153 = \textbf{0.35 V}\\\text{The cell potential is }\large\boxed{\textbf{0.35 V}}$