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Dennis_Churaev [7]
4 years ago
13

LAWS OF SINE

Mathematics
1 answer:
astraxan [27]4 years ago
7 0

By the law of sines,

\dfrac{\sin49^\circ}{AB}=\dfrac{\sin53^\circ}{18\,\mathrm{ft}}\implies AB=\dfrac{(18\,\mathrm{ft})\sin49^\circ}{\sin53^\circ}\approx17.0\,\mathrm{ft}

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