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Luda [366]
3 years ago
12

What is x for -7=9x-7

Mathematics
2 answers:
FromTheMoon [43]3 years ago
8 0

Answer:


Step-by-step explanation:

-7=9x-7

Rewrite the equation

9x-7=-7

Add 7 both sides

9x=7-7

Subtract 7-7 right side

9x=0

Divide 9 both sides

X= 0/9

Solved

X= 0

To check

9x-7 = -7

9(0)-7= -7

-7=-7

It checks



givi [52]3 years ago
5 0

x equals zero

-7=9x-7

Add the -7 over: 0=9x

Divide both sides by 9: 0=x

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Which statement describes the polygon? A. The polygon is equilateral but not equiangular. B. The polygon is equiangular but not
matrenka [14]
B.t<span>he polygon is equiangular but not equilateral. this should be correct </span>
5 0
3 years ago
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PLSS ANSWER MY QUESTION
Taya2010 [7]

Answer:

1) Area of frame: 140cm^2 ; Area of picture: 40cm^2 ; Total Area: 180cm^2.      

2) Area 1 =  48cm^2 ; Area 2 = 12cm^2 ; total area = 60cm^2 [first answer line : 60cm^2]

Step-by-step explanation:

1. So to answer this question, you have to find the inner photo area first (which you will then subtract from the overall rectangle area to get the photo frame area).

To find area, you multiply length x width. For this question, there are not enough measurements given to initially multiply length and width. So, assuming that the photo is centered on the frame and the frame width is consistent along all sides, you find the difference between the overall length (12) and the picture length (5).

12 - 5 = 7

The leftover area (outside of the picture) is 7 cm (half of seven on both sides), so one side can be assumed to be : 3.5 cm

this means that 15 cm - 3.5 cm of both sides lengths (difference between the two lengths given) is the height of the photo, 15 - 3.5(2) = 8

So, the dimensions/measurements of the photo are 5 cm by 8 cm.

This means that the inner photo area is 40 (5 x 8) cm

The area of the frame will be the area of the total rectangle [12 x 15] - the inner photo area [40].  [ (12)(15) - 40 ]

[180 - 40] = 140 cm

(area is measured in squared units, so the area of the frame should be written as 140cm^{2} ; and the area of the photo should be written as 40cm^{2})

The total area is the entire area of the rectangle: (12)(15) = 180. (This should be written as 180cm^2)

--------------------------------------

2) Finding the area of a shape that isn't a simple rectangle is easier if you separate the shape into smaller rectangles. I will separate the two rectangles into 4 x 12 and 2 x 6 [6 cm would be the remaining side length if you remove the length of 4].

{you can separate the shape in multiple ways, so my answer is only one answer to this problem out of other splits.}

as mentioned, the area is length x width.

4 x 12 = 48.

2 x 6 = 12. Once again, you should write area in squared units.

(the area 1 should be written as 48cm^{2} ; the area 2 should be written as 12cm^2)

you can combine the separated areas (add them) to find the total area. 48 + 12 = 60.

(the total area should be written in squared units also, so the total area should be written as: 60cm^2)

The area of the figure is 60cm^2

8 0
2 years ago
Pls asap... use trigonometry to find the area of a regular 20- gon with each side = 6 in
irga5000 [103]

Answer:

Area of polygon[20 sides] = 1,140 inch² (Approx.)

Step-by-step explanation:

Given;

Number of sides = 20 sides

Length of each side = 6 inch

Find:

Area of polygon[20 sides]

Computation:

Perimeter of polygon[20sides] = 20 x Length of each side

Perimeter of polygon[20sides] = 20 x 6

Perimeter of polygon[20sides] = 120 inch

Apothem[Shortest distance from center] = S / 2tan[180/n]

Apothem[Shortest distance from center] = 6 / 2tan[180/20]

Apothem[Shortest distance from center] = 6 / 2tan[9]

Apothem[Shortest distance from center] = 18.94

Apothem[Shortest distance from center] = 19 inch (Approx.)

Area of polygon[20 sides] = [Perimeter x Apothem] / 2

Area of polygon[20 sides] = [120 x 19] / 2

Area of polygon[20 sides] = 1,140 inch² (Approx.)

6 0
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Identify each shape as translation, rotation and reflection​
Wewaii [24]
1 reflection, 2 rotation,
7 0
3 years ago
In a certain city, 80 percent of the households have cable television and 60 percent of the households have videocassette record
alexandr1967 [171]

Answer:

60,000

Step-by-step explanation:

Let the total people in the household be 100%

If 80 percent of the households have cable television, 60 percent of the households have videocassette recorders and the number of households that have both cable television and videocassette recorders is 'x' percent. The number of households having ONLY cable television will be 80-x while households having ONLY videocassette will be 60-x.

To get x, we will have;

80-x + 60-x + x = 100

140-x = 100

x = 140-100

x = 40

This shows that 40% of the households have both cable television and videocassette.

If there are 150,000 households in the city, then the number of households that have both cable television and videocassette recorders could be 40% of 150,000

= 40/100 × 150,000

= 60,000

Number of households that owns both television and videocassette could be from 60,000.

3 0
3 years ago
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