One scarf=s
One hat=h
2s+h=13
s+2h=14
h=13-2s
(plug that into the other equation)
s+2(13-2s)=14
s+26-4s=14
26-3s=14
-3s=-12
s=4
One hat=$5
One scarf=$4
5+4=9
Price of one hat AND one scarf is $9
Answer:
(1-2b)/126b^2
Step-by-step explanation:
(7b-14b^2)/(42b^2*21b)
factor out the 7b,
[7b(1-2b)]/882b^3
[7b(1-2b)]/[7b(126b^2)]
cancel out the 7b's
(1-2b)/126b^2
The value of the y coordinate of any point on the x axis is always 0.
<u><em>Explanation</em></u>
Suppose, the co ordinate of any point is 
.
It means, the distance of the point from x-axis is '
' and distance from y-axis is '
'.
Now if the point lies on the x-axis, that means the distance of the point from x-axis will be 0. Thus, the value of '' will be 0.
So, the value of the y coordinate of any point on the x axis is always 0.
Answer:
<h2>
x = 16 degrees</h2>
Step-by-step explanation:
1 and 3 are <u>vertical angles</u> so m∠1 = m∠3
(4x - 2)° = 62°
4x - 2 = 62
4x = 64
x = 16
Answer with explanation:
→→→Function 1
f(x)= - x²+ 8 x -15
Differentiating once , to obtain Maximum or minimum of the function
f'(x)= - 2 x + 8
Put,f'(x)=0
-2 x+ 8=0
2 x=8
Dividing both sides by , 2, we get
x=4
Double differentiating the function
f"(x)= -2, which is negative.
Showing that function attains maximum at ,x=4.
Now,f(4)=-4²+ 8× 4-15
= -16 +32 -15
= -31 +32
=1
→→→Function 2:
f(x) = −x² + 2 x − 3
Differentiating once , to obtain Maximum or minimum of the function
f'(x)= -2 x +2
Put,f'(x)=0
-2 x +2=0
2 x=2
Dividing both sides by , 2, we get
x=1
Double differentiating the function,gives
f"(x)= -2 ,which is negative.
Showing that function attains maximum at ,x=1.
f(1)= -1²+2 ×1 -3
= -1 +2 -3
= -4 +2
= -2
⇒⇒⇒Function 1 has the larger maximum.
