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hichkok12 [17]
3 years ago
14

PLEASE HELP! i have a couple minutes left

Mathematics
2 answers:
swat323 years ago
8 0

Answer:

1.8

Step-by-step explanation:

slope formula: (y2-y1)/(x2-x1)

(86-32)/(30-0)

54/30

1.8

Olin [163]3 years ago
6 0

Answer:

Im just guessing here because i havent done this in a while but i think the answer is 1.8

Step-by-step explanation:

  1. I used the slope formula y2-y1 over x2-x1
  2. So placed the corridanats in and i got 32-86 over o-30
  3. I then subtracted 86 from 32 and got -54
  4. I subtracted 30 from 0 and got -30
  5. Then i divided -54 by -30 and got 1.8
  6. aI hope this helps i havent done this in a while
  7. (good luck)
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Answer:

The family of possible values for p are:

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Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|} (1)

Where:

\theta - Angle between vectors, in sexagesimal degrees.

\|\vec a\|, \|\vec b \| - Norms of vectors \vec {a} and \vec{b}

If \theta is acute, then the cosine function is bounded between 0 a 1 and if we know that \vec {a} = (p, 3, -7) and \vec {b} = (p, -p, 4), then the possible values for p are:

Minimum (\cos \theta = 0)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0

Maximum (\cos \theta = 1)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1

With the help of a graphing tool we get the family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

7 0
3 years ago
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Slav-nsk [51]

Complete question:

CHECK ATTACHMENT FOR THE DIAGRAM.

Answer:

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Step-by-step explanation:

From the diagram, notice that angle 4 = angle 5

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