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Jet001 [13]
3 years ago
5

If a=2,c=4 e=-6 then 3a-3(2c-e)

Mathematics
2 answers:
Sloan [31]3 years ago
6 0
Its 36 your welcome people
Gnom [1K]3 years ago
4 0
The answer will be negative 36
HOPE IT HELPS,
 
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Anne has a broken ruler. It starts at the 3-inch mark and ends at the 12-inch mark. Explain how Anne could use the ruler to meas
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She would start at the 3 inch mark and count from there.
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3 years ago
Aaron works as a bar attendant and receives $11 per hour. On Saturday he works for five hours at normal time and three hours ove
scoundrel [369]

Answer:

so his total pay for Saturday would be $104.50

Step-by-step explanation:

He works 5 hours at $11  per hour which gets a total of 55$

He also works 3 hours of overtime where he gets payed 1.5x pay

11 x 1.5 = 16.5 (10x1.5 = 15 1x1.5 = 1.5)

so he gets $16.5 per hour for 3 hours which = 49.5$

49.5 + 55 = $104.50

5 0
3 years ago
Whats the answer? Ben rents a car for one day. The charge is $20 plus the $0.12 per mile. He wants to spend exactly $80. How man
vladimir1956 [14]

Answer: The cost for the mileage is . 12m

8 0
2 years ago
Read 2 more answers
Could someone pls help me and explain this if you know it!!
yanalaym [24]

Answer:

25% on question one

Step-by-step explanation:

For example, on question one, 5 students drink more than half a dozen sodas a week. If there is a total of 20 students you'd divide 5 by 20 and that should be the answer.

8 0
3 years ago
The average student loan debt for college graduates is $25,150.
Aleks04 [339]

Using the normal distribution, it is found that:

a) X \approx N(25150, 12050)

b) There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

c) Low: $23,519.65, High: $26,580.35.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 25150, \sigma = 12050.

Hence the distribution of X can be described as follows:

X \approx N(25150, 12050)

The probability that the college graduate has between $14,200 and $33,950 in student loan debt is the <u>p-value of Z when X = 33950 subtracted by the p-value of Z when X = 14200</u>, hence:

X = 33950:

Z = \frac{X - \mu}{\sigma}

Z = \frac{33950 - 25150}{12050}

Z = 0.73

Z = 0.73 has a p-value of 0.7673.

X = 14200:

Z = \frac{X - \mu}{\sigma}

Z = \frac{14200 - 25150}{12050}

Z = -0.91

Z = -0.91 has a p-value of 0.1814.

0.7673 - 0.1814 = 0.5859.

There is a 0.5859 = 58.59% probability that the college graduate has between $14,200 and $33,950 in student loan debt.

Considering the symmetry of the normal distribution, the middle 10% is between the 45th percentile(X when Z = -0.127) and the 55th percentile(X when Z = 0.127), hence:

Z = \frac{X - \mu}{\sigma}

-0.127 = \frac{X - 25150}{12050}

X - 25150 = -0.127(12050)

X = $23,519.65.

Z = \frac{X - \mu}{\sigma}

0.127 = \frac{X - 25150}{12050}

X - 25150 = 0.127(12050)

X = $26,580.35.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

5 0
2 years ago
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