Which of the following do plants gain from sunlight?
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Your question is incomplete. However, I found a similar problem fromanother website as shown in the attached picture.
To solve this problem, you must know that at STP, the volume for any gas is 22.4 L/mol. So,
Moles O₂: 156.8 mL * 1 L/1000 mL* 1 mol/22.4 L = 0.007 moles
Mass calcium: 0.007 mol O₂ * 2 mol Ca/1 mol O₂ * 40 g/mol Ca =<em> 0.56 g Ca</em>
To solve this problem, you must know that at STP, the volume for any gas is 22.4 L/mol. So,
Moles O₂: 156.8 mL * 1 L/1000 mL* 1 mol/22.4 L = 0.007 moles
Mass calcium: 0.007 mol O₂ * 2 mol Ca/1 mol O₂ * 40 g/mol Ca =<em> 0.56 g Ca</em>
Step 1 : Write balanced chemical equation
The balanced chemical equation for the reaction between iodine gas and chlorine gas is given below.
Step 2 : Set up ICE table
We will set up an ICE table for the above reaction
Following points are considered while drawing ICE table
- The initial concentration of product is assumed as 0
- The change in concentration (C) is assumed as x. Change (x) is negative for reactants and positive for products
- The coefficients in balanced equation are considered while writing C values
Check attached file for ICE table
Step 3 : Set up equilibrium constant equation
The equation for equilibrium constant can be written as
Step 4 : Solving for x
Keq at 298.15 K is given as 81.9
Let us plug in the equilibrium values (E) for I₂, Cl₂ and ICl from ICE table
81.9 =
81.9 =
Solving the above equation using quadratic formula we get
x = 0.488 or x = 0.254
The value 0.488 cannot be used because the change (C) cannot be greater that initial concentration of the reactants.
Therefore the change in concentration of the gases during the reaction is 0.254 M
Hence, x = 0.254 M
From the ICE table, we know that the equilibrium concentration of ICl is 2x
The concentration of ICl when the reaction reaches equilibrium is 0.508 M
Answer:
A) During this procedure ( hypoventilation ) The CO2 in the arterial blood vessels and the lungs increases and this drives the PH level in the system lower, and the equilibrium will shift to the right. this is because the Blood-PH level is controlled by CO2 - bicarbonate buffer system
B) The blood PH may rise to 7.60 during Hyperventilation because the removal of CO2 from the lungs causes the increase in which is directly proportional to the increase in Blood PH levels
C) Hyper ventilation before a dash would be useful because it will remove excessive Hydrogen ions and and raise the Blood PH levels in preparedness of the production of acids like Lactic acid
Explanation:
A) During this procedure ( hypoventilation ) The CO2 in the arterial blood vessels and the lungs increases and this drives the PH level in the system lower, and the equilibrium will shift to the right. this is because the Blood-PH level is controlled by CO2 - bicarbonate buffer system
⇄
B) The blood PH may rise to 7.60 during Hyperventilation because the removal of CO2 from the lungs causes the increase in which is directly proportional to the increase in Blood PH levels
C) Hyper ventilation before a dash would be useful because it will remove excessive Hydrogen ions and and raise the Blood PH levels in preparedness of the production of acids like Lactic acid