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Advocard [28]
3 years ago
10

Hello,

Chemistry
2 answers:
Ulleksa [173]3 years ago
8 0

Answer:

In talc preparation, it is used during the filtration process and also acts as a distribution agent. When it is added to the dill water, it combines with all other compounds present in the substance and leaves the water alone. In this way, it acts as a filtering agent.

Explanation:

it has already been answered

Vladimir79 [104]3 years ago
7 0

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In talc preparation, it is used during the filtration process and also acts as a distribution agent. When it is added to the dill water, it combines with all other compounds present in the substance and leaves the water alone. In this way, it acts as a filtering agent.

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Identify the reactants and products in the following chemical equation: Zn +2HCl --&gt; ZnCl2 + H2 *
Ad libitum [116K]

Answer:

A.

Explanation:

zinc and hydrochloric acid reacts to form zinc chloride and hydrogen.

hope it helps. :)

7 0
3 years ago
Fe(s) + 2HCl(aq) --&gt; FeCl2(aq) + H2(g)
soldier1979 [14.2K]

Answer:

In the option(A) moles of HCl left are 0.100 moles which is wrong, making the option incorrect.

Explanation:

Fe(s) + 2HCl(aq)\rightarrow  FeCl_2(aq) + H_2(g)&#10;

Moles of HCl = n

Molarity of HCl = 1.0M

Volume of HCl solution = 30.0 mL = 0.030 L (1 mL = 0.001L)

Moles=Molarity\times Volume (L)

n=1.0M\times 0.030 L=0.030 mol

Moles of Fe = \frac{0.56 g}{56 g/mol}=0.01 mol

According to recation , 1mol of Fe reacts with 2 mol HCl. Then 0.01 mole of Fe will recat with :

\frac{2}{1}\times 0.01 mol= 0.02 mol of HCl

This means that HCl uis in excess , hence excessive reagent.

Moles of HCl left unreacted :

= 0.030 mol - 0.020 mol = 0.010 mol

But in the option moles of HCl left are 0.100 moles which is wrong, making the option incorrect.

8 0
3 years ago
Water can act as both an acid and a base in an ionization reaction to form (H) and OH ions.
matrenka [14]
Sorry I need points :)
4 0
3 years ago
Read 2 more answers
Push your palms again a wall. What happened
kondaur [170]

Answer:

It felt good!!!

Why do you ask??

3 0
4 years ago
In this reaction, what is the substance oxidized? zn(s) + 2 hcl(aq) → zncl2(aq) + h2(g) zinc chloride chlorine hydrogen zn oxyge
Zarrin [17]
Zn(s) + 2 HCl(aq) → ZnCl₂(aq) + H₂(g) 
Oxidation means lose of electrons and increase of positive charge so the part which oxidized in this equation is Zn(s) because it converted to Zn²⁺ (i.e. lost two electrons) 
7 0
3 years ago
Read 2 more answers
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