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Advocard [28]
3 years ago
10

Hello,

Chemistry
2 answers:
Ulleksa [173]3 years ago
8 0

Answer:

In talc preparation, it is used during the filtration process and also acts as a distribution agent. When it is added to the dill water, it combines with all other compounds present in the substance and leaves the water alone. In this way, it acts as a filtering agent.

Explanation:

it has already been answered

Vladimir79 [104]3 years ago
7 0

<h2>\huge{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}</h2>

In talc preparation, it is used during the filtration process and also acts as a distribution agent. When it is added to the dill water, it combines with all other compounds present in the substance and leaves the water alone. In this way, it acts as a filtering agent.

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How many grams of NO can be made from 50 g of NH3?<br><br> 4 NH3 + 5 O2 → 6 H2O + 4 NO
Evgen [1.6K]
0.08 because 4mol NO divided by 50g gives you your answer
4 0
2 years ago
Last time I'm asking this, answer, this time, 50 points.
EleoNora [17]

Explanation:

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6 0
3 years ago
• We obtained the above 10.00-mL solution by diluting a stock solution using a 1.00-mL aliquot and placing it into a 25.00-mL vo
garik1379 [7]

Answer:

a) The relationship at equivalence is that 1 mole of phosphoric acid will need three moles of sodium hydroxide.

b) 0.0035 mole

c)  0.166 M

Explanation:

Phosphoric acid is tripotic because it has 3 acidic hydrogen atom surrounding it.

The equation of the reaction is expressed as:

H_3PO_4 \ + \ 3NaOH -----> Na_3 PO_4 \ + \ 3H_2O

1 mole         3 mole

The relationship at equivalence is that 1 mole of phosphoric acid will need three moles of sodium hydroxide.

b)  if 10.00 mL of a phosphoric acid solution required the addition of 17.50 mL of a 0.200 M NaOH(aq) to reach the endpoint; Then the molarity of the solution is calculated as follows

H_3PO_4 \ + \ 3NaOH -----> Na_3 PO_4 \ + \ 3H_2O

10 ml            17.50 ml

(x) M              0.200 M

Molarity = \frac{0.2*17.5}{1000}

= 0.0035 mole

c) What was the molar concentration of phosphoric acid in the original stock solution?

By stoichiometry, converting moles of NaOH to H₃PO₄; we have

= 0.0035 \ mole \ of NaOH* \frac{1 mole of H_3PO_4}{3 \ mole \ of \ NaOH}

= 0.00166 mole of H₃PO₄

Using the molarity equation to determine the molar concentration of phosphoric acid in the original stock solution; we have:

Molar Concentration =  \frac{mole \ \ of \ soulte }{ Volume \ of \ solution }

Molar Concentration = \frac{0.00166 \ mole \ of \  H_3PO_4 }{10}*1000

Molar Concentration = 0.166 M

∴  the molar concentration of phosphoric acid in the original stock solution = 0.166 M

6 0
4 years ago
A solution containing equal numbers of hydrogen ions and hydroxide ions is
igor_vitrenko [27]

Answer:

The answer to your question is: Neutral

Explanation:

A neutral solution is a solution whose pH is 7.

That means that this solution has the same amount of H⁺ and OH⁻.

Examples of neutral solutions:

- distilled water

- sugar solution

- table salt

- cooking oil.

4 0
3 years ago
Question 2 3 pts Which solution is the most acidic?​
Drupady [299]

Answer:

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Explanation:

6 0
3 years ago
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