Bond energy refers to the energy that must be taken in to break a bond. It is also the energy required to form the bond.
<h3>What is Bond energy?</h3>
The term bond energy refers to the energy that must be taken in to break a bond. It is also the energy required to form the bond.
The energy that must be supplied to break the bonds in two molecules of HCl is 862 J. The energy released is obtained from; 862J - [436 +262] = 164J.
The total energy of the reaction is 164J, this is called the enthalpy change. Based on this value of the total energy, the reaction is endothermic. Hence, it is true that; "It takes more energy to break the two H–Cl bonds than is released when forming the H–H and Cl–Cl bonds."
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8.25 grams of O2 has 0.258 moles of Oxygen. Here's how you figure that out:
Oxygen is one of the 7 diatomic elements, so it is normally O2.
<span>You find it's molar mass (or mass for </span>one mole<span> of it) by adding up two of the masses from the Periodic Table.</span>
Answer:
The answer to your question is 23.4 moles of Glucose
Explanation:
Data
moles of Oxygen = ?
moles of glucose = 3.9
-Balanced chemical reaction
1C₆H₁₂O₆ + 6O₂ ⇒ 6H₂O + 6CO₂
Process
1.- To solve this problem, use the coefficient of the balanced chemical equation, and use proportions and cross multiplication.
1 mol of C₆H₁₂O₆ -------------------- 6 moles of O₂
3.9 moles of C₆H₁₂O₆ ------------------ x
x = (3.9 x 6 ) / 1
x = 23.4 moles
2.- Conclusion
3.9 moles of glucose consume 23.4 moles of oxygen
Answer:
its 19 I'm pretty sure about
Answer:
5 L
Explanation:
We'll begin by calculating the molarity of the CaCl₂ solution. This can be obtained as follow:
Mole of CaCl₂ = 0.5 mole
Volume = 2 L
Molarity =?
Molarity = mole /Volume
Molarity = 0.5 / 2
Molarity = 0.25 M
Finally, we shall determine the volume of the diluted solution. This can be obtained as follow:
Molarity of stock solution (M₁) = 0.25 M
Volume of stock solution (V₁) = 2 L
Molarity of diluted solution (M₂) = 0.1 M
Volume of diluted solution (V₂) =?
M₁V₁ = M₂V₂
0.25 × 2 = 0.1 × V₂
0.5 = 0.1 × V₂
Divide both side by 0.1
V₂ = 0.5 / 0.1
V₂ = 5 L
Thus the volume of the diluted solution is 5 L
