The atom must have gained 1 or more electrons or must have lost 1 or more electrons.
Answer:
q = 0.0392 / V, for V= 0.1V q = 0.392 C
Explanation:
For this exercise we can assume that the power energy of the drops is transformed into kinetic energy, therefore we use the conservation of energy
starting point
Em₀ = U = q V
final point
Em_f = K = ½ m v²
Em₀ = Em_f
q V = ½ m v²
q =
let's calculate
q = ½ 0.40 10⁻³ 14² / V
q = 0.0392 / V
The object to be painted is connected to ground therefore its potential is dro, but the gun where it is painted has a given potential, suppose it is
V = 0.1 V
q = 0.0392 / 0.1
q = 0.392 C
Answer:
m = 47.5 Kg
Explanation:
given,
speed of skater toward north, v = 0.8 m/s
momentum of the skater in north, P = 38 Kg.m/s
mass of the skater = ?
we now,
Momentum is equal to the product of mass and velocity
P = m x v
38 = m x 0.8
m = 47.5 Kg
hence, mass of the skater is equal to 47.5 Kg.
Answer:
a) F = 2.7 10⁻¹⁴ N
, b) a = 2.97 10¹⁶ m / s² c) θ = 14º
Explanation:
The magnetic force on the electron is given by the expression
F = q v x B
Which can be written in the form of magnitude and the angle found by the rule of the right hand
F = q v B sin θ
where θ is the angle between the velocity and the magnetic field
a) the maximum magnitude of the force occurs when the velocity and the field are perpendicular, therefore, without 90 = 1
F = e v B
F = 1.6 10⁻¹⁹ 2.40 10⁶ 7.10 10⁻²
F = 2.73 10⁻¹⁴ N
F = 2.7 10⁻¹⁴ N
b) Let's use Newton's second law
F = m a
a = F / m
a = 2.7 10⁻¹⁴ / 9.1 10⁻³¹
a = 2.97 10¹⁶ m / s²
The actual acceleration (a1) is a quarter of this maximum
a1 = ¼ a
a1 = 7.4 10¹⁵ m / s²
With this acceleration I calculate the force that is executed on the electron
F = ma
e v b sin θ= ma
sin θ = ma / (e v B)
sin θ = 9.1 10⁻³¹ 7.4 10¹⁵ / (1.6 10⁻¹⁹ 2.40 10⁶ 7.10 10⁻²)
sin θ = 6.734 10⁻¹⁵ / 27.26 10⁻¹⁵
sin θ = 0.2470
θ = 14.3º
Answer:
In-car temperature is controlled in a variable displacement compressor system by varying the capacity of the <em>refrigeration</em> not by cycling the <em>compressor </em>on and off.
Explanation:
A Variable Displacement Compressor (VDC) works in a separate and rather more efficient manner than the fixed displacement compressor (FDC). <em>The VDC automatically regulates the cooling effect of the refrigerator by changing its pumping capacity by means of a "wobbling piston" system. </em>
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During times of peak load, the refrigeration pumping capacity is increased, delivering a large flow rate of refrigerant, thus giving a high refrigerating effect. The reverse happens during times of load refrigeration load.
<em>The fixed compressor tries to vary the temperature of the car by simply switching off the compressor</em>, and turning it on during times of low and peak loads.