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hichkok12 [17]
3 years ago
11

Read the passage about an athlete.

Physics
1 answer:
KATRIN_1 [288]3 years ago
3 0
I think the answer is b
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A team of dogs pulls a sled across the snow. The weight of the loaded sled is 2,200 N. The coefficient of friction is 0.15. How
chubhunter [2.5K]
.. The weight of the loaded sled is 2200 N. The coefficient of friction is 0.15. How hard must the dogs pull so that their effort just equals the frictional force? ... to move after the light changes from red to green A team of dogs pulls a sled across the snow. ... 2) pulling force of dogs fL = us N = 0.15 x2200 = 330 <span>N

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7 0
4 years ago
Read 2 more answers
Rank the angular speed of the following objects, from highest to lowest:- A bowling ball of radius 12.3 cm rotating at 8.21 radi
dlinn [17]

Answer:

A bowling ball (8.21rad/s) > A tire (7.94rad/s) > A square (7.75rad/s) > A rock (6.98rad/s) > A top spinning (6.54rad/s)

Explanation:

<u>To rank the angular speed (ω) of the objects, we need first calculate its value for every object:</u>

A bowling ball of radius 12.3cm rotating at 8.21 radians per second:

ω = 8.21 rad/s

A tire of radius 0.321m rotating at 75.8 rpm:

\omega = 75.8 \frac{rev}{min}\cdot \frac{2\pi rad}{1rev}\cdot \frac{1min}{60s} = 7.94rad/s

A 6.84cm diameter top spinning at 375 degrees per second:

\omega = 375 \frac{^\circ}{s}\cdot \frac{2\pi rad}{360^ \circ} = 6.54rad/s    

A square with sides (b) 0.458m long, whose corners are moving with tangential speed (v) 2.51 m/s as it rotates about its center:

\omega = \frac{v}{r} = \frac{v}{\frac{b}{2}\sqrt 2} = \frac{2.51 m/s}{\frac{0.458 m}{2} \sqrt 2} = 7.75rad/s

A rock on a string, being swung in a circle of radius 0.521 m with a centripetal acceleration (a) of 25.4 m/s²:

\omega = \sqrt \frac{a}{r} = \sqrt \frac{25.4 m/s^{2}}{0.521m} = 6.98rad/s

<u>Now, the rank of the angular speed of the objects, from highest to lowest is: </u>

A bowling ball (8.21rad/s) > A tire (7.94rad/s) > A square (7.75rad/s) > A rock (6.98rad/s) > A top spinning (6.54rad/s) 

I hope it helps you!      

4 0
3 years ago
What type of plant tissue is NOT part of the vascular bundle?
jek_recluse [69]

Answer:

Cortex

Explanation:

3 0
3 years ago
Read 2 more answers
Accurate radiometric dating typically requires that a rock contains a measurable amount of __________.
gizmo_the_mogwai [7]

Answer:

Both daughter and parent atoms

Explanation:

Daughter atoms are an offshoot of daughter elements, and are formed when a radioactive element undergoes radioactive decay. The new element is the daughter element, while the initial, the former element is the parent element.

Same analogy goes for daughter atoms and parent atoms..

Radiometric dating is also called radioactive dating or even radioisotope dating. It is a technique that is used to date materials like carbon or even rocks, that has trace radioactive impurities selectively incorporated into it when they were formed.

4 0
3 years ago
If F(theta)=tan theta=3, find F(theta+pi)
Alex_Xolod [135]
The period of the tan function is π so (∅ + π) would yield the same value as ∅
F(∅ + π) = 3
4 0
3 years ago
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