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FromTheMoon [43]
3 years ago
8

A 0.5-kg ball moving at 5 m/s strikes a wall and rebounds in the opposite direction with a speed of 2 m/s. If the impulse occurs

for a time duration of 0.01 s, then the average force (magnitude only) acting upon the ball is ____ Newtons.
Physics
1 answer:
mart [117]3 years ago
6 0

<em>Given that:</em>

                       mass of the ball (m) = 0.5 Kg ,

                    ball strikes the wall (v₁) = 5 m/s ,

rebounds in opposite direction (v₂) = 2 m/s,

                                time duration (t) = 0.01 s,

        <em> Determine the force (F) = ?</em>

We know that from Newton's II law,

                                <em>F = m. a</em>  Newtons  

                                  (velocity acting in opposite direction, so <em>a = ( (v₁ + v₂)/t</em>

                                   = m × (v₁ + v₂)/t

                                   = 0.5 × (5 + 2)/0.01

                                  = 350 N

<em>The force acting up on the ball is 350 N</em>

                                     

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