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FromTheMoon [43]
3 years ago
8

A 0.5-kg ball moving at 5 m/s strikes a wall and rebounds in the opposite direction with a speed of 2 m/s. If the impulse occurs

for a time duration of 0.01 s, then the average force (magnitude only) acting upon the ball is ____ Newtons.
Physics
1 answer:
mart [117]3 years ago
6 0

<em>Given that:</em>

                       mass of the ball (m) = 0.5 Kg ,

                    ball strikes the wall (v₁) = 5 m/s ,

rebounds in opposite direction (v₂) = 2 m/s,

                                time duration (t) = 0.01 s,

        <em> Determine the force (F) = ?</em>

We know that from Newton's II law,

                                <em>F = m. a</em>  Newtons  

                                  (velocity acting in opposite direction, so <em>a = ( (v₁ + v₂)/t</em>

                                   = m × (v₁ + v₂)/t

                                   = 0.5 × (5 + 2)/0.01

                                  = 350 N

<em>The force acting up on the ball is 350 N</em>

                                     

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PART ONE
Korvikt [17]

Answer:

1) 460.5 N

2) 431.7 N

Explanation:

Draw a free body diagram.  There are four forces on the hammer:

Applied force 62.5 N in the +x direction, 30 cm from the ground

Reaction force Rᵧ in the +y direction, at the point of contact

Reaction force Rₓ in the +x direction, at the point of contact

Reaction force F at 31° from the vertical, 4.75 cm to the left of the point of contact

Part One

To find F, sum the moments about the point of contact:

∑τ = Iα

(62.5 N) (30 cm) − (F cos 31°) (4.75 cm) = 0

F = 460.5 N

Part Two

To find Rₓ and Rᵧ, sum the forces in the x and y directions.

∑Fₓ = ma

62.5 N − F sin 31° + Rₓ = 0

Rₓ = 174.7 N

∑Fᵧ = ma

-F cos 31° + Rᵧ = 0

Rᵧ = 394.7 N

The net reaction force at the point of contact is:

R = √(Rₓ² + Rᵧ²)

R = 431.7 N

7 0
3 years ago
Explain why Earth is not a perfect sphere?
miss Akunina [59]
The answer is C hope it helped
6 0
2 years ago
A pilot heads her jet due east. The jet has a speed of 425 mi/h relative to the air (in other words, if the air were still, the
Elza [17]

Answer:

The resultant velocity of the jet as a vector in component form 426.87 mi/hr 5.36 degrees North.

Explanation:

Vectors are quantities that have their magnitude and direction .

Sketching out the problem given, by using straight lines to represent each of the vectors, we will have a right angled triangle as shown below.

The solution can be obtained by applying Pythagoras theorem to

resolve the vectors.

Velocity of jet plane = 425 mi/hr

velocity of air = 40 mi/hr

Resultant of the vectors =\sqrt[]{425^{2}+40^{2}}=426.87 mi/hr

Vector direction =tan^{-1}(\frac{40}{425})= 5.36 degrees

hence the velocity is 426.87 mi/hr in a direction 5.36 degrees inclined Northward

5 0
3 years ago
A 2 kg object is
Mademuasel [1]
NO net force is required to keep a moving object moving in a straight
line at a constant speed.  In fact, if you apply ANY force to it, in ANY
direction, then its speed, its direction, or both must change, and its
velocity won't be uniform any more. 

I know we never see this in our daily life.  Whenever we see an object
moving, it always stops.  That's because the net force on it is never zero ...
there's always some gravity or some friction acting on it.  That's what you
have to put up with when you live on Earth.
8 0
3 years ago
1. A body has a velocity of 72 km/hr. Find its value in m/s.
CaHeK987 [17]

72 Km/hr

= 72000 m/ 60×60 s

= 72000 m/ 3600 s

= 20 m/s

Answer is 20 m/s.

Hope it helps! Please do comment

8 0
3 years ago
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