A 0.5-kg ball moving at 5 m/s strikes a wall and rebounds in the opposite direction with a speed of 2 m/s. If the impulse occurs
1 answer:
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The speed of a proton after it accelerates from rest through a potential difference of 350 V is .
Initial velocity of the proton
Given potential difference
let's assume that the speed of the proton is ,
Since the proton is accelerating through a potential difference, proton's potential energy will change with time. The potential energy of a particle of charge when accelerated with a potential difference
is,
Due to Work-Energy Theorem and Conservation of Energy - <em>If there is no non-conservative force acting on a particle then loss in Potential energy P.E must be equal to gain in Kinetic Energy K.E</em> i.e
If the initial and final velocity of the proton is and
respectively then,
change in Kinetic Energy
change in Potential Energy
from conservation of energy,
so,
To read more about the conservation of energy, please go to brainly.com/question/14668053
Answer:
I=1.48 A
Explanation:
Given that
B=3.1 x 10⁻5 T
b= 4.2 cm
l= 9.5 cm
The relationship for magnetic field and current given as
Where
By putting the values
D=26.03 m⁻¹
I=1.48 A
Answer:
2.25in³
Explanation:
For a 12 awg conductor the minimum volume allowance as stated by the NEC is 2.25in³
See attached Table 314.16(B) from NEC 2011
