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Leya [2.2K]
3 years ago
10

the table shows the concentration of a reactant in the reaction mixture over a period of time. what is the average rate of the r

eaction over the first 450 seconds?
Chemistry
1 answer:
Stella [2.4K]3 years ago
6 0

The question is missing the table. Here is the complete question.

The tableshows the concentration of a reactant in the mixture over a period of time.

Reactant Concentration

Time (s)         Concentration (M)

    0                       1.8

  210                      1.2

 450                      0.8

 580                      0.6

 720                      0.4

What is the average rate of reaction over the first 450 seconds?

A. 1.6x10^{-3} M

B. 1.9x10^{-3} M

C. 2.0x10^{-3} M

D. 2.2x10^{-3} M

Answer: D. 2.2x10^{-3} M

Explanation: The average rate of a reaction is the rate of change of the concentrations (of reactants or products) in a period of time:

average = - ΔC/Δt

In this case, concentration is negative because it's related to reactant, since its concentration dimishes while the concentration of product increases.

For the first 450 seconds:

Average = \frac{-(0.8 - 1.8)}{450 - 0}

Average = \frac{1}{450}

Average = 0.0022

or

Average = 2.2x10^{-3}

So, <u>the Average Rate of the reaction is 2.2x</u>10^{-3}<u>M</u>

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a) T_{2} = 360.955\,K, P_{2} = 138569.171\,Pa\,(1.386\,bar), b) T_{2} =  347.348\,K, V_{2} = 0.14\,m^{3}

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b) The ideal gas is experimenting an isobaric process and the following relationship is used:

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V_{2} = \frac{347.348\,K}{298\,K}\cdot (0.12\,m^{3})

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