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denis23 [38]
3 years ago
6

According to the ,cell theory where do cells come from?

Chemistry
1 answer:
NikAS [45]3 years ago
7 0

Answer:

cells come from pre existing cells

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Caustic Soda

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Milk of Magnesia

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Explanation:

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How many grams of potassium nitrate (KNO3) would form if 2.25 liters of a 1.50 molar lead nitrate Pb(NO3)2 solution reacts with
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I know that the answer is 639 g
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Read the scientific question below.
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If we fertilize a plant, then its height increases fast. Always use if then format
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What is the molecular formula for a monocyclic hydrocarbon with 14 carbons and 2 triple bonds?
liq [111]

The molecular formula for a monocyclic hydrocarbon with 14 carbons and 2 triple bond is C₁₄H₂₀

<h3>Molecular formula</h3>

A formula that gives the number of atom of each element present in a one molecule or a compound.

<h3>Monocyclic hydrocarbons</h3>

The name of the saturated hydrocarbons formed by the name attaching the perfix cyclo to the name of acyclic unstaturated hydrocarbon

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brainly.com/question/11558543

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7 0
2 years ago
Read 2 more answers
How many moles of Cu(OH)2 are soluble in 1L of sodium hydroxide (NaOH) when the pH is 8.23?
Morgarella [4.7K]

Answer:

4.96E-8 moles of Cu(OH)2

Explanation:

Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.

Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.

pH= -log[H]\\pH= -log (\frac{kw}{[OH]})

8.23 = - log(\frac{Kw}{[OH]} \\10^{-8.23} = Kw/[OH]\\ [OH] = Kw/10^{-8.23}

[OH]=1.69E-6

This concentration of OH affects the disociation of Cu(OH)2. Let us see the dissociation reaction:

Cu(OH)_2 -> Cu^{2+} + 2OH^-

In the equilibrum, exist a concentration of OH already, that we knew, and it will be added that from dissociation, called "s":

The expression for Kps is:

Kps= [Cu^{2+}] [OH]^2

The moles of (CuOH)2 soluble are limitated for the concentration of OH present, according to the next equation.

Kps= s*(2s+1.69E-6)^2

"s" is the soluble quantity of Cu(OH)2.

The solution for this third grade equation is s=4.96E-8 mol/L

Now, let us calculate the moles in 1 L:

moles Cu(OH)_2 = 4.96E-8 mol/L * 1 L = 4.96E-8 moles

7 0
4 years ago
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