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Black_prince [1.1K]
3 years ago
11

There are two open cans of soda on the table. One can was just taken from the refrigerator and the other was taken from the cupb

oard. Upon opening the cans, which one loses carbon dioxide more quickly and why? A.The can from the refrigerator. Because it is colder and gases are less soluble in colder temperatures. B.The can from the refrigerator, because it is colder and gases are more soluble in colder temperatures. C.The can from the cupboard, because it is warmer and gases are less soluble in warmer temperatures. D.Neither, because the solubility of gases is affected only by pressure.
Chemistry
2 answers:
kvv77 [185]3 years ago
7 0

The correct answer is

C- The can from the cupboard, because it is warmer and gases are less soluble in warmer temperatures

:)

nika2105 [10]3 years ago
5 0
I think the correct answer from the choices listed above is option C. The can <span>from the cupboard will lose carbon dioxide more quickly because it is warmer and gases are less soluble in warmer temperatures. </span> Solubility of gases is a strong function of temperature and as well as pressure.
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Make sure have same amounts of species on both sides
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Determine how many grams of N2 are produced from the reaction of 8.37 g of H2O2 and 5.29 g of N2H4.
Dmitriy789 [7]
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mol = mass ÷ molar mass

If mass of hydrazine (N₂H₄)  = 5.29 g 
then mol of hydrazine           = 5.29 g ÷ ((14 ×2) + (1 × 4))
                                              = 0.165 mol

mole ratio of hydrazine to Nitogen is     1   :  1
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Mass = mol × molar mass

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5 0
3 years ago
Balance the following redox equation in acidic solution using the smallest integers possible and select the correct coefficient
romanna [79]

Answer:

Coefficient of H^{+}(aq) is more than 4

Explanation:

Oxidation: Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)

  • Balance charge: Sn^{2+}(aq)-2e^{-}\rightarrow Sn^{4+}(aq)......(1)

Reduction: Cr_{2}O_{7}^{2-}(aq)\rightarrow Cr^{3+}(aq)

  • Balance Cr: Cr_{2}O_{7}^{2-}(aq)\rightarrow 2Cr^{3+}(aq)
  • Balance O and H in acidic medium: Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)\rightarrow 2Cr^{3+}(aq)+7H_{2}O(l)
  • Balance charge: Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)+6e^{-}\rightarrow 2Cr^{3+}(aq)+7H_{2}O(l).......(2)

[3\times Equation-(1)]+Equation(2) gives balanced equation:

3Sn^{2+}(aq)+Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)\rightarrow 3Sn^{4+}(aq)+2Cr^{3+}(aq)+7H_{2}O(l)

So coefficient of H^{+}(aq) is more than 4

3 0
3 years ago
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