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PIT_PIT [208]
2 years ago
11

7) If £1 = €1.14. Work out what €144 is in pounds.

Mathematics
1 answer:
jonny [76]2 years ago
8 0

Answer:

126\frac{6}{19} £

Step-by-step explanation:

£1 = €1.14  /*\frac{144}{1.14}

£\frac{144}{1.14}=144€= 126\frac{6}{19} \\£

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2 years ago
Find a set of parametric equations of the line with the given characteristics. (Enter your answer as a comma-separated list of e
emmainna [20.7K]

This question is incomplete, the complete question is;

Find a set of parametric equations of the line with the given characteristics. (Enter your answer as a comma-separated list of equations in terms of x, y, z, and t.) The line passes through the point (3, 1, 2) and is parallel to the line given by x  = y = z.

Answer:

the set of parametric equations of the line with the given characteristics are; x = t+3, y = t+1, z = t+2

Step-by-step explanation:

Given that;

line x = y = z and point ( 3, 1, 2 )

the given line can be written as;

[x-0 / 1] = [y-0 / 1] = [z-0 / 1]

if two lines are parallel directional ratios are equal.

so DIRECTIONAL RATIOS  of given line is ( 1, 1, 1 )

therefore required line is;

[x-3 / 1] = [y-1 / 1] = [z-2 / 1] = t

⇒ [x-3 / 1] = t

x = t+3

[y-1 / 1] = t

y = t+1

[z-2 / 1] = t

z = t+2

Therefore the set of parametric equations of the line with the given characteristics are; x = t+3, y = t+1, z = t+2

8 0
3 years ago
The radius of a circle is 7 miles. What is the circumference?
Fiesta28 [93]

The circumference is ~43.98 miles.

4 0
2 years ago
Please help me !!!!!!!!
astraxan [27]
It's C the missing side is 9 units long so since cosine is adjacent divided by hypotenuse it would be 9/41
5 0
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Read 2 more answers
Suppose the weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams. The weights
user100 [1]

Answer:

a) 0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b) The weight that 80% of the apples exceed is of 78.28g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams.

This means that \mu = 85, \sigma = 8

a. Find the probability a randomly chosen apple exceeds 100 g in weight.

This is 1 subtracted by the p-value of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 85}{8}

Z = 1.875

Z = 1.875 has a p-value of 0.9697

1 - 0.9696 = 0.0304

0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b. What weight do 80% of the apples exceed?

This is the 100 - 80 = 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.

Z = \frac{X - \mu}{\sigma}

-0.84 = \frac{X- 85}{8}

X - 85 = -0.84*8

X = 78.28

The weight that 80% of the apples exceed is of 78.28g.

5 0
2 years ago
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