Question

If 5400. Joules of energy were supplied to 4.5 grams of ice at -10 degree Celsius, how many grams of what phases would you have?

Answer 1

Answer is: 3,66 g of liquid water and 0,84 g of vapor.
1) Q₁ = m·C·ΔT
Q₁ = 4,5 g · 2,108 J/°C·g · 10°C.
Q₁ = 97,86 J heat required to warm the ice to 0°C.
2) Q₂ = 4,5 g · 334 J/g.
Q₂ = 1503 J heat required to melt the ice to water at 0°C.
3) Q₃ = 4,5 g · 4,184 J/°C·g · 100°C
Q₃ = 1882,28 J heat required to warm the water from 0°C to 100°C.
Q₄ = 5400 J - 3483,14 J = 1916,86 J heat left to vapourize the water.
m(vapor) = 1916,86 J ÷ 2257 J/g = 0,84 g.

Answer 2

The answers to you questions are 3,66 g of liquid water and 0,84 g of vapor.
Solution:1) Q₁ = mxCxΔT = 4,5 g x 2,108 J/°C x g x 10°C.
 = 97,86 J heat required to warm the ice to 0°C.

2) = 4,5 g x 334 J/g. = 1503 J heat required to melt the ice to water at 0°C.

3)  = 4,5 g  x 4,184 J/°C x g x 100°C
 = 1882,28 J heat required to warm the water from 0°C to 100°C. = 5400 J - 3483,14 J = 1916,86 J heat left to vaporize the water.

mass of the vapor= 1916,86 J ÷ 2257 J/g
= 0,84 g.