Answer:
(A) 0.004 m^3
(B) 48.11 K
Explanation:
Work, W = 2100 J
Pressure, P = 1 x 10^5 Pa
V2 = 0.025 m^3
(A) let the initial volume of the gas is V1.
W = P (V2 - V1)
2100 = 1 x 10^5 (0.025 - V1)
0021 = 0.025 - V1
V1 = 0.025 - 0.021
V1 = 0.004 m^3
Thus, the initial volume of the gas is 0.004 m^3.
(B) Let the temperature of the gas is T
Use ideal gas equation
P1 x V1 = n x R T
1 x 10^5 x 0.004 = 1 x 8.314 x T
T = 48.11 K
Thus, the initial temperature of the gas is 48.11 K.
