All categories

3 years ago

If there are 20 waves in a 5-second time frame, what is the frequency?

Physics

2 answers:

mestny [16]3 years ago

6 0

Answer:

The frequency is four waves per second.

Explanation:

You make it so the time is one second.

To do that you divide 5 seconds by 5.

Since you divide the seconds by 5 you now have to divide the amount of waves by 5.

20/5=4 5/5=1

Now your answer is four waves per second.

creativ13 [48]3 years ago

3 0

Your answer would be 0.20 Hz

You might be interested in

Which is an example of a mixture?

fgiga [73]

The answer is: B. Trail Mix

7 0

3 years ago

Read 2 more answers

pogonyaev

Answer:

Explanation:

4 0

2 years ago

Question 10 of 10

svetoff [14.1K]

Answer:

Explanation:

f=ma

200=2*m

divide both sides by 2

m=100

6 0

3 years ago

Calculate the solubility (in m units) of ammonia gas in water at 298 k and a partial pressure of 2.50 bar . the henry's law cons

Eduardwww [97]

Henry's Law (formulated in 1803 by William Henry) states that aa constant temperature, the amount of gas dissolved in a liquid is directly proportional to the partial pressure exerted by that gas on the liquid.
Mathematically it can be formulated as
C = H⨯P
being:
C: the molar concentration of dissolved gas A,
P: the partial pressure of it
H: Henry's constant
Substituting:
C = P * H
C = (2.50 * 0.9869) * 58.0
C = 143.1
Answer:
the solubility (in m units) is
C = 143.1

8 0

3 years ago

An automobile with a mass of 1240.00 kg has 3.99 m between

Vitek1552 [10]

Answer:

$948.15248\ N$

$5134.04751\ N$

Explanation:

$F_f$ = Force on front wheels

$F_r$ = Force on rear wheels

Distance between CG and rear wheel = 3.99-0.622 = 3.368 m

$F_r=1240\times 9.81-F_f$

As the forces are conserved we have

$(1240\times 9.81-F_f)3.368=F_f\times 0.622\\\Rightarrow 12164.4-F_f=\dfrac{0.622F_f}{3.368}\\\Rightarrow 12164.4-F_f=0.18467F_f\\\Rightarrow F_f=\dfrac{12164.4}{1.18467}\\\Rightarrow F_f=10268.09503\ N$

On rear wheels

$F_r=1240\times 9.81-10268.09503\\\Rightarrow F_r=1896.30497\ N$

The force on each rear whees is $\dfrac{1896.30497}{2}=948.15248\ N$

Force on each front wheel is $\dfrac{10268.09503}{2}=5134.04751\ N$

8 0

3 years ago