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Digiron [165]
2 years ago
9

If there are 20 waves in a 5-second time frame, what is the frequency?

Physics
2 answers:
mestny [16]2 years ago
6 0

Answer:

The frequency is four waves per second.

Explanation:

You make it so the time is one second.

To do that you divide 5 seconds by 5.

Since you divide the seconds by 5 you now have to divide the amount of waves by 5.

20/5=4 5/5=1

Now your answer is four waves per second.

creativ13 [48]2 years ago
3 0
Your answer would be 0.20 Hz
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Enzo investigated the effect of different types of fertilizers on the growth of bean plants. He hypothesized that fertilizer B w
Mama L [17]

Answer:

The answer is "In this information, Enzo will be confident that if any fertilizer is required only for plants".

Explanation:

The Beans plants were members of the group of legumes. Legume flowering plant under which the roots form nodules. These nodules require a specific bacterium called bacteria, which fix nitrogen. Its bacterium transforms nitrogen from the atmosphere into the soil's nitrate. Consequently, for some of its growth, beans do not require fertilizer.

4 0
3 years ago
You and your friend are going bungee jumping! You wait directly below them with a camera. When they leap from the bridge they be
Alex

Answer:

The amplitude  is  A =  90.2 \ m

Explanation:

From the question we are told that

    The frequency of when sound is approaching observer is   f = 392 Hz

     The frequency as the move away from observer  is  f_ a =  330 \ Hz

    The time between the pitch are t =  10 \ s

Here you are the observer and your friends are the source of the sound

The period is mathematically evaluated as

       T =  2 t

as it is the time to complete one oscillation which from on highest pitch to the next highest pitch

Now T can also be mathematically represented as

          T = \frac{2 \pi}{w}

Where  w is the angular velocity

=>   \frac{2 \pi}{w}  =  2 * 10

=>   w =  0.314 \ rad/sec

Now using Doppler Effect,

   The source of the sound is approaching the observer

The

          f = f_o (\frac{v}{v- wA} )

         392  = f_o (\frac{v}{v- wA} )

Where A is the amplitude

    So when the source is moving away from the observer

         f_a =  f_o (\frac{v}{v+ wA} )  

        330  =  f_o (\frac{v}{v+ wA} )  

Here  f_o is the fundamental frequency

Dividing the both equation  we have

           \frac{392}{330}  =  \frac{f_o(\frac{v}{v-wA} )}{f_o(\frac{v}{v+wA}}

           1.1878  = \frac{v+wA}{v-wA}

         1.1878 v -  1.1878 wA = v+wA

        1.1878 v = 2.1878 wA

=>     A =  \frac{(0.1878 * (330))}{(2.1878)* (0.314)}

         A =  90.2 \ m

7 0
3 years ago
Cindy runs 500 meters every morning. It takes her 2 hours to complet
marta [7]

Answer:

250 / 2.5*10^2

Explanation:

7 0
1 year ago
The Hubble Space Telescope orbits the Earth at approximately 612,000m altitude. Its mass is 11,100 kg and the mass of earth is 5
nexus9112 [7]

Answer:

7.55 km/s

Explanation:

The force of gravity between the Earth and the Hubble Telescope corresponds to the centripetal force that keeps the telescope in uniform circular motion around the Earth:

G\frac{mM}{R^2}=m\frac{v^2}{R}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant

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R=r+h=6.38\cdot 10^6 m+612,000 m=6.99\cdot 10^6 m is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)

v = ? is the orbital velocity of the Hubble telescope

Re-arranging the equation and substituting numbers, we find the orbital velocity:

v=\sqrt{\frac{GM}{R}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24} kg)}{6.99\cdot 10^6 m}}=7548 m/s=7.55 km/s

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Solenoid is another word for
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Answer: coil of wire
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3 years ago
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