Answer:
The greatest number of groups he could have made is 4 groups
Each of the four groups will have:
4 Squares each
7 circles each
Step-by-step explanation:
16 squares
28 circles
Find the highest common factor of 16 and 28
16: 1, 2, 4, 8, 16
28: 1, 2, 3, 4, 7, 14, 28
The highest common factor of 16 and 28 is 4
This means the greatest number of groups he could have made is 4 groups
Each of the four groups will have:
16 squares = 16 / 4
= 4 Squares each
28 circles = 28 / 4
= 7 circles each
Each of the four groups will have:
4 Squares each
7 circles each
Number one, is 430 divided by 18. 430/18 = 23.8888889 = rounding the number should make 23.4
im just gonna take the points for falling for that.
11.5x+22 equal to -13x+218
11.5x+22=-13x+218
Now you have an equation. Solve for x:
11.5x+22+13x=-13x+13x+218 (add 13x to both sides)
24.5x+22=218
24.5x+22-22=218-22 (subtract 22 from both sides)
24.5x=196
x=196÷24.5
x=8
After 8 weeks their balances would be the same.
Their balances will be:
11.5x+22=11.5(8)+22=114$
and
-13x+218=-13(8)+218=114$
So, 114$ each.
Hope this was helpful.
Answer is 188
3x2 - 5xy + 5y2
Now put x = -6 and y = 2
3(-6)2 - 5(-6)(2) + 5(2)2
3(36) - 5(-12) + 5(4)
108 + 60 + 20
188
